我有一个包含Null值的表。我需要将它们替换为以前的非null值。 这是我拥有的数据的示例:
date | category | start_period | period_number |
------------------------------------------------------
2018-01-01 | A | 1 | 1 |
2018-01-02 | A | 0 | Null |
2018-01-03 | A | 0 | Null |
2018-01-04 | A | 0 | Null |
2018-01-05 | B | 1 | 2 |
2018-01-06 | B | 0 | Null |
2018-01-07 | B | 0 | Null |
2018-01-08 | A | 1 | 3 |
2018-01-09 | A | 0 | Null |
2018-01-10 | A | 0 | Null |
结果应如下所示:
date | category | start_period | period_number |
------------------------------------------------------
2018-01-01 | A | 1 | 1 |
2018-01-02 | A | 0 | 1 |
2018-01-03 | A | 0 | 1 |
2018-01-04 | A | 0 | 1 |
2018-01-05 | B | 1 | 2 |
2018-01-06 | B | 0 | 2 |
2018-01-07 | B | 0 | 2 |
2018-01-08 | A | 1 | 3 |
2018-01-09 | A | 0 | 3 |
2018-01-10 | A | 0 | 3 |
我尝试了以下查询,但是在这种情况下,仅第一个Null值将被替换。
select
date,
category,
start_period,
case
when period_number isnull then lag(period_number) over()
else period_number
end as period_number
from period_table;
此外,我尝试使用first_value()
窗口功能,但我不知道如何设置正确的窗口。
我们非常感谢您的帮助。
答案 0 :(得分:0)
如果您将case语句替换为:
(
select
_.period_number
from
period_table as _
where
_.period_number is not null
and _.category = period_table.category
and _.date <= period_table.date
order by
_.date desc
limit 1
) as period_number
然后它将具有预期的效果。它远没有窗口函数那么优雅,但我认为窗口函数在这里对于您的特定用例没有足够的灵活性(或者,至少,如果它们是,我不知道如何灵活调整它们)>
答案 1 :(得分:0)
您可以将表与其自身连接并获得所需的值。假设您的日期列是主键或唯一键。
update your_table upd set period_number = tbl.period_number
from
(
select b.date, max(b2.date) as d2 from your_table b
inner join d_batch_tab b2 on b2.date< b.date and b2.period_number is not null
group by b.date
)t
inner join your_table tbl on tbl.date = t.d2
where t.date= upd.date
如果您不需要更新表,而只需更新一条选择语句,则
select yt.date, yt.category, yt.start_period, tbl.period_number
from your_table yt
inner join
(
select b.date, max(b2.date) as d2 from your_table b
inner join d_batch_tab b2 on b2.date< b.date and b2.period_number is not null
group by b.date
)t on yt.date = t.date
inner join your_table tbl on tbl.date = t.d2
答案 2 :(得分:0)
windows函数和frame子句的例子:
select
date,category,score
,FIRST_VALUE(score) OVER (
PARTITION BY category
ORDER BY date RANGE BETWEEN UNBOUNDED
PRECEDING AND CURRENT ROW
) as last_score
from testing.rec_test
order by date, category
select
date,category,score
,LAST_VALUE(score) OVER (
PARTITION BY category
ORDER BY date RANGE BETWEEN CURRENT ROW AND UNBOUNDED FOLLOWING
) as last_score
from testing.rec_test
order by date, category