当tabAt [i]不为null时，为什么ConcurrentHashMap不使用'CAS'而是使用'synchronized'

Question

final V putVal(K key, V value, boolean onlyIfAbsent) {
if (key == null || value == null) throw new NullPointerException();
int hash = spread(key.hashCode());
int binCount = 0;
for (Node<K,V>[] tab = table;;) {
    Node<K,V> f; int n, i, fh;
    if (tab == null || (n = tab.length) == 0)
        tab = initTable();
    else if ((f = tabAt(tab, i = (n - 1) & hash)) == null) {
        if (casTabAt(tab, i, null,
                     new Node<K,V>(hash, key, value, null)))
            break;                   // no lock when adding to empty bin
    }
    else if ((fh = f.hash) == MOVED)
        tab = helpTransfer(tab, f);
    else {
        V oldVal = null;
        synchronized (f) {
            if (tabAt(tab, i) == f) {
                if (fh >= 0) {
                    binCount = 1;
                    for (Node<K,V> e = f;; ++binCount) {
                        K ek;
                        if (e.hash == hash &&
                            ((ek = e.key) == key ||
                             (ek != null && key.equals(ek)))) {
                            oldVal = e.val;
                            if (!onlyIfAbsent)
                                e.val = value;
                            break;
                        }
                        Node<K,V> pred = e;
                        if ((e = e.next) == null) {
                            pred.next = new Node<K,V>(hash, key,
                                                      value, null);
                            break;
                        }
                    }
                }
                else if (f instanceof TreeBin) {
                    Node<K,V> p;
                    binCount = 2;
                    if ((p = ((TreeBin<K,V>)f).putTreeVal(hash, key,
                                                   value)) != null) {
                        oldVal = p.val;
                        if (!onlyIfAbsent)
                            p.val = value;
                    }
                }
            }
        }
        if (binCount != 0) {
            if (binCount >= TREEIFY_THRESHOLD)
                treeifyBin(tab, i);
            if (oldVal != null)
                return oldVal;
            break;
        }
    }
}
addCount(1L, binCount);
return null;

}

当tabAt(tab, i = (n - 1) & hash))为null时，它将使用CAS来添加/修改节点，但是当其不为null时，它将使用synchronized (f)。我认为它仍然可以使用最后一个节点的CAS或带有tabAt(tab, i = (n - 1) & hash))的键的节点来添加/修改节点。但是为什么不呢？我的想法是错误的。