Question

我想计算单个字符以字符串但连续的方式出现。

<?php 
echo $strin = "abcaaabbcccccdaasvvbbvvtteesgggg";
echo "</br>";
$str_l = strlen($strin);
$i  = $j = 0;
$temp_c = "";
for($i;$i<$str_l;$i++){
$j = 0;
$j = substr_count($strin, $strin[$i]);
 echo $strin[$i]." is repeated ".$j." times </br>";
}
?>

Answer 1

您可以执行此操作-

$string = "abcaaabbcccccdaasvvbbvvtteesgggg";
// Split string by character and convert to array
$temp = str_split($string);
// Count values present in array
array_count_values($temp);

输出

Array ( [a] => 6 [b] => 5 [c] => 6 [d] => 1 [s] => 2 [v] => 4 [t] => 2 [e] => 2 [g] => 4 )

JavaScript scrollTo method does nothing?

array_count_values()

连续出现

// split and create array with unique characters
$new = array_unique(str_split($string));
$chars = [];
foreach($new as $c) {
   // regex check for character's multiple occurrences 
   preg_match_all("/($c)\\1+/", $string, $matches);
   // Store the count
   $chars[$c] = count($matches[0]);
}
print_r($chars);

Outpur

Array
(
    [a] => 2
    [b] => 2
    [c] => 1
    [d] => 0
    [s] => 0
    [v] => 2
    [t] => 1
    [e] => 1
    [g] => 1
)

php函数substr_count如何工作？

1 个答案: