Question

我有以下三个字符串列表：

st1=["a","b"]
st2=["likes"]
st3=["programming","math"]

我希望输出如下：

a likes programming
b likes math

Answer 1

使用itertools.cycle

from itertools import cycle

st1=["a","b"]
st2=["likes"]
st3=["programming","math"]

for i,j,k in zip(st1, cycle(st2), st3):

    print(i+" "+j+" "+k)

输出：

a likes programming                                                                                                                   
b likes math

Answer 2

如果st1和st3的长度相同，请尝试以下操作：

print(*[st1[i]+" "+st2[0]+" "+st3[i] for i in range(len(st1))], sep = '\n')

输出：

a likes programming
b likes math

Answer 3

将zip_longest与for循环一起使用：

for x,y,z in zip_longest(st1,st2*2,st3):
     print(x,y,z)

或者：

print('\n'.join([' '.join(i) for i in zip_longest(st1,st2*2,st3)]))

演示：

from itertools import zip_longest
st1=["a","b"]
st2=["likes"]
st3=["programming","math"]
for x,y,z in zip_longest(st1,st2*2,st3):
     print(x,y,z)

其他演示：

from itertools import zip_longest
st1=["a","b"]
st2=["likes"]
st3=["programming","math"]
print('\n'.join([' '.join(i) for i in zip_longest(st1,st2*2,st3)]))

Answer 4

完全动态的解决方案，您可以根据需要提供任意数量的大小不同的数组：

def generate_output(*args):
  max_length = max([len(arg) for arg in args])
  for i in range(max_length):
    tmp = ""
    for arg in args:
      if len(arg) < max_length:
        arg = arg + [arg[-1]] * (max_length - len(arg))
      tmp += arg[i] + " "
    print tmp

st1 = ['a','b']
st2 = ['likes']
st3 = ['programming','math','Bio']
st4 = ['and','or']
st5 = ['he']
st6 = ['loves']
st7 = ['piano','games', 'sport', 'reading']

generate_output(st1,st2,st3)
print('***')
generate_output(st1,st2,st3,st4,st5,st6,st7)

输出：

a likes programming 
b likes math 
b likes Bio 
***
a likes programming and he loves piano 
b likes math or he loves games 
b likes Bio or he loves sport 
b likes Bio or he loves reading

如OP示例中所示，当计算超出数组的总长度以将其与其他较长的数组连接时，将使用数组的最后一个元素。

我有三个单独的列表，我想按顺序将它们连接起来

4 个答案: