我需要json
响应中的这段代码,并希望我可以在android中轻松调用它的请求url
。我只想在android中调用此网络服务。
public JsonResult LoginPatient(Patients lc)
{
string mainconn =
ConfigurationManager.ConnectionStrings["dhc"].ConnectionString;
SqlConnection sqlconn = new SqlConnection(mainconn);
string sqlquery = "select PatientEmail,PatientPassword from [dbo].[Patients] where PatientEmail=@PatientEmail and PatientPassword=@PatientPassword";
sqlconn.Open();
SqlCommand sqlcomm = new SqlCommand(sqlquery, sqlconn);
sqlcomm.Parameters.AddWithValue("@PatientEmail", lc.PatientEmail);
sqlcomm.Parameters.AddWithValue("@PatientPassword",lc.PatientPassword);
SqlDataReader sdr = sqlcomm.ExecuteReader();
if (sdr.Read())
{
Session["PatientEmail"] = lc.PatientEmail.ToString();
}
else
{
ViewData["Message"] = "Patient Login Details Failed ";
}
sqlconn.Close();
return Json (View());
}
我想在android
中称呼它来登录患者。所以我想要一个URL
。如何获得?