Question

我想并行运行pyqt5 QThreads，但我的代码似乎按顺序运行，有人可以告诉我如何并行运行QThreads吗？

我的代码的输出：我希望它并行运行，而不是顺序运行。

Multithreading with maximum 4 threads
You pressed the Test button
Job 1
Job 2
Job 3
Job 4
Done.
THREAD COMPLETE!

代码：

from PyQt5.QtGui import *
from PyQt5.QtWidgets import *
from PyQt5.QtCore import *

import time
import traceback, sys

uart_result = ['1','2', '3', '4', '5', '6']

#Running all these methods in parallel
@pyqtSlot()
def run1():
    print("Job 1")
    return uart_result

@pyqtSlot()
def run2():
    print("Job 2")
    return uart_result

@pyqtSlot()
def run3():
    print("Job 3")
    return uart_result

@pyqtSlot()
def run4():
    print("Job 4")
    return uart_result

class WorkerSignals(QObject):
    finished = pyqtSignal()
    error = pyqtSignal(tuple)
    result = pyqtSignal(object)
    list = pyqtSignal(list)
    progress = pyqtSignal(int)


class Worker(QRunnable):

    def __init__(self, fn, *args, **kwargs):
        super(Worker, self).__init__()

        # Store constructor arguments (re-used for processing)
        self.fn = fn
        self.args = args
        self.kwargs = kwargs
        self.signals = WorkerSignals()

        # Add the callback to our kwargs
        self.kwargs['progress_callback'] = self.signals.progress

    @pyqtSlot()
    def run(self):
        '''
        Initialise the runner function with passed args, kwargs.
        '''

        # Retrieve args/kwargs here; and fire processing using them
        try:
            result = self.fn(*self.args, **self.kwargs)
        except:
            traceback.print_exc()
            exctype, value = sys.exc_info()[:2]
            self.signals.error.emit((exctype, value, traceback.format_exc()))
        else:
            self.signals.result.emit(result)  # Return the result of the processing
        finally:
            self.signals.finished.emit()  # Done



class MainWindow(QMainWindow):

    def __init__(self, *args, **kwargs):
        super(MainWindow, self).__init__(*args, **kwargs)
        layout = QVBoxLayout()
        b = QPushButton("START!")
        b.pressed.connect(self.runner)
        layout.addWidget(b)
        w = QWidget()
        w.setLayout(layout)
        self.setCentralWidget(w)
        self.show()

        self.threadpool = QThreadPool()
        print("Multithreading with maximum %d threads" % self.threadpool.maxThreadCount())


    def execute_this_fn(self, progress_callback):
        command_list=[run1, run2, run3, run4]
        for i in range(4):
            command_list[i]()

        return "Done."
    #this not printing the global list.
    def print_output(self, uart_list):
        print(uart_list)

    def thread_complete(self):
        print("THREAD COMPLETE!")

    def runner(self):
        print("You pressed the Test button")
        # Pass the function to execute
        worker = Worker(self.execute_this_fn) # Any other args, kwargs are passed to the run function
        worker.signals.result.connect(self.print_output)
        worker.signals.finished.connect(self.thread_complete)

        # Execute
        self.threadpool.start(worker)

app = QApplication([])
window = MainWindow()
app.exec_()

Answer 1

您必须为每个任务创建一个Worker（QRunnable），在这种情况下，您仅为其创建了一个任务（任务按顺序执行）：

from PyQt5 import QtCore, QtGui, QtWidgets

import time
import traceback, sys

uart_result = ['1','2', '3', '4', '5', '6']

#Running all these methods in parallel
@QtCore.pyqtSlot()
def run1():
    print("Job 1")
    return uart_result

@QtCore.pyqtSlot()
def run2():
    print("Job 2")
    return uart_result

@QtCore.pyqtSlot()
def run3():
    print("Job 3")
    return uart_result

@QtCore.pyqtSlot()
def run4():
    print("Job 4")
    return uart_result

class WorkerSignals(QtCore.QObject):
    finished = QtCore.pyqtSignal()
    error = QtCore.pyqtSignal(tuple)
    result = QtCore.pyqtSignal(object)
    progress = QtCore.pyqtSignal(int)


class Worker(QtCore.QRunnable):
    def __init__(self, fn, *args, **kwargs):
        super(Worker, self).__init__()
        self.fn = fn
        self.args = args
        self.kwargs = kwargs
        self.signals = WorkerSignals()
    def run(self):
        try:
            result = self.fn(*self.args, **self.kwargs)
        except:
            traceback.print_exc()
            exctype, value = sys.exc_info()[:2]
            self.signals.error.emit((exctype, value, traceback.format_exc()))
        else:
            self.signals.result.emit(result)  # Return the result of the processing
        finally:
            self.signals.finished.emit()  # Done



class MainWindow(QtWidgets.QMainWindow):
    def __init__(self, *args, **kwargs):
        super(MainWindow, self).__init__(*args, **kwargs)
        b = QtWidgets.QPushButton("START!")
        b.pressed.connect(self.runner)

        w = QtWidgets.QWidget()
        layout = QtWidgets.QVBoxLayout(w)
        layout.addWidget(b)
        self.setCentralWidget(w)

    def print_output(self, uart_list):
        print(uart_list)

    def thread_complete(self):
        print("THREAD COMPLETE!")

    def runner(self):
        thread_pool = QtCore.QThreadPool.globalInstance()
        print("Multithreading with maximum %d threads" % thread_pool.maxThreadCount())
        print("You pressed the Test button")
        for task in (run1, run2, run3, run4):
            worker = Worker(task)
            worker.signals.result.connect(self.print_output)
            worker.signals.finished.connect(self.thread_complete)
            thread_pool.start(worker)

if __name__ == '__main__':
    import sys
    app = QtWidgets.QApplication(sys.argv)
    window = MainWindow()
    window.show()
    sys.exit(app.exec_())

QThreadPool不是按顺序运行，是什么导致我的代码线程不能并行运行？

1 个答案: