Question

我有一个背景AVAudioPlayer，通常可以正常工作。现在，我有一些事件会延迟触发异步动作，在这里我想播放另一种声音，而另一种声音应该继续播放。所以我做了一个新的：

DispatchQueue.main.asyncAfter(deadline: .now() + 1) {
    guard let urlStr = Bundle.main.path(forResource: "File1", ofType: ".mp3") else { fatalError() }
    self.player = try? AVAudioPlayer(contentsOf: URL(fileURLWithPath: urlStr), fileTypeHint: "mp3")
    self.player?.play()
}

DispatchQueue.main.asyncAfter(deadline: .now() + 2) {
    guard let urlStr = Bundle.main.path(forResource: "File2", ofType: ".mp3") else { fatalError() }
    let p = try? AVAudioPlayer(contentsOf: URL(fileURLWithPath: urlStr), fileTypeHint: "mp3")
    p?.play()
}

因此第一个运行正常（仅调度以表明它也在异步运行）。第二个也运行，这意味着没有错误。但是，我只听到第一个...

Answer 1

Why do you create a new player inside you async call? I had similar problems and it should work if you declare a new var outside your immediate async-scope.

同时异步播放多个AVAudioPlayer？

1 个答案: