Question

我有以下代码段：

function [S,r1,r2,c1,c2] = xor2imgs(org,templete,Diff)
    while (r+O - 1) <= N
           while (c+P - 1) <= M
               if sum_temp <= sum(sum(sum(org(r:r+O-1,c:c+P-1)))) %cond #1              
                   matrix = org;
                   matrix(r:r+O-1,c:c+P -1) = org(r:r+O-1,c:c+P-1)-templete(1:O,1:P); 
                   mat_sum = sum(sum(sum(matrix)));
                   diff2 = org_sum-mat_sum;               
                   if (mat_sum == diff) && (diff2 > Diff) %cond #2
                       S = org_sum-mat_sum; 
                       r1 = r;
                       r2 = r1+O-1;
                       c1 = c;
                       c2 = c1+P-1;
                       return ; %must return to the original function yet keep the output values 
                   end
               end
           end
        end 
end

使用return后，我应该怎么做才能将[S，r1，r2，c1，c2]的值传递给调用方函数？我将函数调用为

 [S,r1,r2,c1,c2] = xor2imgs(org,newtemplete,S);

在另一个函数中，但它每次输出始终返回零。...

Answer 1

我假设所有变量都在while循环上方定义...

您可以使用多个break语句。之所以需要多个break语句，是因为您有嵌套循环，而一个break语句就不够用。我在您的代码中添加了一个计数器变量，以在您需要跳出循环时更改为1：

counter = 0;
function [S,r1,r2,c1,c2] = xor2imgs(org,templete,Diff)
    while (r+O - 1) <= N
        while (c+P - 1) <= M
            if sum_temp <= sum(sum(sum(org(r:r+O-1,c:c+P-1)))) %cond #1              
                matrix = org;
                matrix(r:r+O-1,c:c+P -1) = org(r:r+O-1,c:c+P-1)-templete(1:O,1:P); 
                mat_sum = sum(sum(sum(matrix)));
                diff2 = org_sum-mat_sum;               
                if (mat_sum == diff) && (diff2 > Diff) %cond #2
                    S = org_sum-mat_sum; 
                    r1 = r;
                    r2 = r1+O-1;
                    c1 = c;
                    c2 = c1+P-1;
                    counter = 1;
                    break;
                end
            end
        end
        if isequal(counter,1)
            break;
        end
    end 
end

MATLAB：如何在使用return后保持输出值

1 个答案: