Question

我要删除所有script元素和此处的代码

<?php
$pageFile = <<<EOF
<!DOCTYPE html><html><body>
<script src="aa"></script>
<script src="bb"></script>
<script src="cc"></script>
<div>aaa</div>
</body></html>
EOF;

$dom = new DOMDocument();
$dom->loadHTML($pageFile);

foreach ($dom->getElementsByTagName('script') as $item) {
  $item->parentNode->removeChild($item);
}
$pageFile = $dom->saveHTML();
echo $pageFile;

，但是仍然存在1个script元素。您可以在线here

试用

结果：

<!DOCTYPE html>
<html><body>
<script src="bb"></script><div>aaa</div>
</body></html>

Answer 1

由DOMNodeList返回的$dom->getElementsByTagName是“活动的”。因此，当您删除脚本时，会将其从节点列表中删除，并且列表中的所有元素都将其索引向下移动。然后for循环转到下一个索引，最终跳过所有其他元素。

首先将节点列表转换为数组。

foreach (iterator_to_array($dom->getElementsByTagName('script')) as $item) {
  $item->parentNode->removeChild($item);
}

Answer 2

如果向后迭代，则可以从DOMNodeList修改甚至删除节点： http://php.net/manual/en/class.domnodelist.php#83390 使用：

<?php

namespace App\Events;

use Illuminate\Broadcasting\Channel;
use Illuminate\Broadcasting\InteractsWithSockets;
use Illuminate\Broadcasting\PrivateChannel;
use Illuminate\Contracts\Broadcasting\ShouldBroadcast;
use Illuminate\Foundation\Events\Dispatchable;
use Illuminate\Queue\SerializesModels;
use Illuminate\Broadcasting\PresenceChannel;

class ProfileInvited implements ShouldBroadcast
{
    use Dispatchable, InteractsWithSockets, SerializesModels;

/**
 * Create a new event instance.
 *
 * @return void
 */
    public $message;

    public function __construct($message)
    {
        $this->message = $message;
        $this->dontBroadcastToCurrentUser();
    }

/**
 * Get the channels the event should broadcast on.
 *
 * @return \Illuminate\Broadcasting\Channel|array
 */
    public function broadcastOn()
    {
        return new PrivateChannel('invitation.' . $this->message->to);
    }
}

PHP DOMDocument不会删除所有元素

2 个答案: