在python 3中将模式匹配部分替换为其他值

Question

我想用RD代替ROAD

addr = ['100 NORTH MAIN ROAD',
            '100 BROAD ROAD APT.',
            'SAROJINI DEVI ROAD',
            'BROAD AVENUE ROAD']

输出

output : ['100 NORTH MAIN RD.',
            '100 BROAD RD. APT.',
            'SAROJINI DEVI RD.',
            'BROAD AVENUE RD.']

我尝试了下面提到的代码

new_address=[word.replace("ROAD","RD") for word in addr]

但未获得所需的输出（BROAD也正在被RD取代。）

['100 NORTH MAIN RD.', '100 BRD. RD. APT.', 'SAROJINI DEVIRD.', 'BRD. AVENUE RD.']

Answer 1

在此当前示例中可以执行以下操作：

new_address=[word.replace(" ROAD"," RD.") for word in addr]

或者通常使用regex：

new_address = [re.sub(r'\bROAD\b', 'RD.', w) for w in l]

# ['100 NORTH MAIN RD.', '100 BROAD RD. APT.', 'SAROJINI DEVI RD.', 
#   'BROAD AVENUE RD.']