在Android中使用XPath在XML文件中搜索

Question

我正在Android上开发一个应用程序！

我现在有一点冲突，我想执行一个XPath查询，但我没有到达解决这个问题。

这是我使用的XML文件的一个例子：

<?xml version="1.0"?>
<catalog>
  <book id="bk101">
   <author>Gambardella, Matthew</author>
 <title>XML Developer's Guide</title>
 <genre>Computer</genre>
 <price>44.95</price>
 <publish_date>2000-10-01</publish_date>
 <description>An in-depth look at creating applications 
  with XML.</description>
</book>

<book id="bk102">
 <author>Ralls, Kim</author>
 <title>Midnight Rain</title>
 <genre>Fantasy</genre>
 <price>5.95</price>
 <publish_date>2000-12-16</publish_date>
 <description>A former architect battles corporate zombies, 
  an evil sorceress.</description>
</book>

<book id="bk103">
 <author>Corets, Eva</author>
 <title>Maeve Ascendant</title>
 <genre>Fantasy</genre>
 <price>5.95</price>
 <publish_date>2000-11-17</publish_date>
 <description>After the collapse of a nanotechnology 
  society in England.</description>
 </book>
 </catalog>

我该怎么办？

提前致谢!!

Answer 1

看看这个例子：

import java.io.FileReader;
import javax.xml.xpath.XPath;
import javax.xml.xpath.XPathConstants;
import javax.xml.xpath.XPathFactory;
import org.w3c.dom.Element;
import org.w3c.dom.NodeList;
import org.xml.sax.InputSource;
public class GuestList {
  public static void main(String[] args) throws Exception {
    XPathFactory factory = XPathFactory.newInstance();
    XPath xPath = factory.newXPath();
    NodeList shows = (NodeList) xPath.evaluate("/schedule/show", new InputSource(new FileReader(
        "tds.xml")), XPathConstants.NODESET);
    for (int i = 0; i < shows.getLength(); i++) {
      Element show = (Element) shows.item(i);
      String guestName = xPath.evaluate("guest/name", show);
      String guestCredit = xPath.evaluate("guest/credit", show);
      System.out.println(show.getAttribute("weekday") + ", " + show.getAttribute("date") + " - "
          + guestName + " (" + guestCredit + ")");
    }
  }
}

其余示例如下：http://jexp.ru/index.php/Java_Tutorial/XML/XPath