Question

from google.cloud import pubsub_v1

def run():
  # created full_* vars here...

  future = subscriber.subscribe(full_subscription, print_and_ack_message)

  try:
    future.result()
  except KeyboardInterrupt: # this doesn't work for some reason...
    logging.info("Subscription terminated...")
    future.cancel()
  except BaseException as exc:
    logging.info("Other %s", type(exc))

if __name__ == '__main__':
  run()

由于某些原因，上面的代码无法在python 2.7.15的macOS，zsh，iTerm和pyenv-virtualenv上中断吗？

CTRL + C在带有此代码的终端上失败；什么也没发生，只有^C在输出中可见，并且它既不终止也不打印任何内容。怎么了？

我正在关注docs

Answer 1

您无需在此处使用result方法：

订户是非阻塞的，因此我们必须阻止主线程退出以允许它在后台处理消息。

def run():
    future = subscriber.subscribe(full_subscription, print_and_ack_message)
    try:
        while True:
            time.sleep(1)
    except KeyboardInterrupt:
        future.cancel()

SIGINT在Google pubsub_v1 / python中被忽略

1 个答案: