Django设计功能可检查500错误以获取无效的主机并阻止IP

Question

我正在获得一些有意尝试在我的IP上查找漏洞的机器人，而我所要做的就是手动阻止IP。

例如，以django发送到我的电子邮件中的错误开头

Invalid HTTP_HOST header: '68.183.112.215'. You may need to add '68.183.112.215' to ALLOWED_HOSTS.

Report at /.well-known/security.txt
Invalid HTTP_HOST header: '68.183.112.215'. You may need to add '68.183.112.215' to ALLOWED_HOSTS.

Request Method: GET
Request URL: https://68.183.112.215/.well-known/security.txt

我需要知道错误类型为无效的HTTP_HOST，然后列出IP地址

HTTP_X_REAL_IP = '198.20.70.114'

解析此字段以获取IP

我认为这应该有效

def handler500(request):
    x_forwarded_for = request.META.get('HTTP_X_FORWARDED_FOR')
    if x_forwarded_for:
        ip = x_forwarded_for.split(',')[0]
    else:
        ip = request.META.get('REMOTE_ADDR')

    #check if Invalid HTTP_HOST header
    #if so run script to add ip to blocked ip's

    #if possible let the normal 500 error to be raised
    ....

    #otherwise raise custom error

如果我可以找出错误类型，那么可以尝试一下。厌倦了手动执行此操作。