Question

我该如何只返回一部分对象的响应

var jason = {
"age" : "24",
"hometown" : "Missoula, MT",
"gender" : "male"
};

如果我只想返回键/值对的响应。

"hometown" : "Missoula, MT"

好吧，我是新来的，我想我可以举一个反例，尝试点符号，它只是返回值而不是键

var stations = [
    {id: 1, description: "London", lat: 64.1275, lon: 21.9028, observations: [2]},
    {id: 2, description: "Spain", lat: 65.6856, lon: 18.1002, observations: [1]}
];

如果我循环使用车站[1]。说明，我只会得到值“伦敦”

[
{description: "London"};
{description: "Spain"}
]

Answer 1

此代码循环遍历对象，检查键是否与期望的键匹配，以及值是否与期望的值匹配。如果是这样，则console.log()的格式为key : value。

var jason = {
"age" : "24",
"hometown" : "Missoula, MT",
"gender" : "male"
};
var key = "hometown";
var value = "Missoula, MT";

for (var tempKey in jason) {
  var obj = jason[key];
  
  if (tempKey == key && value == jason[key]) {
    console.log(key + " : " + jason[key]);
  }
}

从响应仅获取Json对象的一部分

1 个答案: