我正在遵循教程(here),并且它已经过时了php,而我的Google搜索没有帮助我,所以我想知道如何使它正常工作?
它显示有500页没有工作(当前无法处理此请求。)
编辑。我忘记添加代码了。
<?php
header('Access-Control-Allow-Origin: *');
$host="localhost"; // Host name
$username="username"; // Mysql username
$password="password"; // Mysql password
$db_name="name"; // Database name
$tbl_name="scores"; // Table name
// Connect to server and select database.
mysql_connect("$host", "$username", "$password")or die("cannot connect");
mysql_select_db("$db_name")or die("cannot select DB");
// Retrieve data from database
$sql="SELECT * FROM scores ORDER BY score DESC LIMIT 10";
$result=mysql_query($sql);
// Start looping rows in mysql database.
while($rows=mysql_fetch_array($result)){
echo $rows['name'] . "|" . $rows['score'] . "|";
// close while loop
}
// close MySQL connection
mysql_close();
?>
我还如何解决此代码?
$dblink = mysql_connect($host,$dbu,$dbp);
$seldb = mysql_select_db($db);
if(isset($_GET['name']) && isset($_GET['score'])){
//Lightly sanitize the GET's to prevent SQL injections and possible XSS attacks
$name = strip_tags(mysql_real_escape_string($_GET['name']));
$score = strip_tags(mysql_real_escape_string($_GET['score']));
$sql = mysql_query("INSERT INTO `$db`.`scores` (`id`,`name`,`score`) VALUES ('','$name','$score');");
if($sql){
//The query returned true - now do whatever you like here.
echo 'Your score was saved. Congrats!';
}else{
//The query returned false - you might want to put some sort of error reporting here. Even logging the error to a text file is fine.
echo 'There was a problem saving your score. Please try again later.';
}
}else{
echo 'Your name or score wasnt passed in the request. Make sure you add ?name=NAME_HERE&score=1337 to the tags.';
}
mysql_close($dblink);//Close off the MySQL connection to save resources.
答案 0 :(得分:1)
以下是使用mysqli的示例
public class A
{
private readonly int i;
public A()
{
Action setI = () => i = 10;
setI();
}
}