如何从包含列表的地图中检索特定值?

时间:2019-03-15 06:43:05

标签: java hibernate spring-mvc

我正在检索列表,并希望从该列表中获得一个要说date的特定列,但是在该特定列中,我只希望日期为2019年,因为该列同时包含2018年和2019。

Iterator<Map<String, Object>> itr = listEnquiry.iterator();
while (itr.hasNext()) {
    map = itr.next();
    CustomerBean bean = (CustomerBean) map.get("customerBean");
    SimpleDateFormat simpleDateFormat = new SimpleDateFormat("yyyy-MM-dd");
    String date = simpleDateFormat.format(bean.getCustomerCreationDate());   // it is giving me date column which contains both year.
}

我得到的输出是-

2018-12-30
2018-12-30
2019-03-13
2018-12-30

但是我想要这样的输出

2019-03-13

那么我该如何接受。我做不到。

1 个答案:

答案 0 :(得分:0)

假设bean.getCustomerCreationDate()返回一个java.util.Date对象,然后尝试在您的while循环底部添加以下内容:

public class Application {

    public static void main(String[] args) {
        HashMap<String, Object> map1 = new HashMap<String, Object>();
        map1.put("customerBean",new CustomerBean("2018-12-30") );
        HashMap<String, Object> map2 = new HashMap<String, Object>();
        map2.put("customerBean",new CustomerBean("2018-03-13") );
        HashMap<String, Object> map3 = new HashMap<String, Object>();
        map3.put("customerBean",new CustomerBean("2018-12-30") );
        HashMap<String, Object> map4 = new HashMap<String, Object>();
        map4.put("customerBean",new CustomerBean("2019-03-01") );
        HashMap<String, Object> map5 = new HashMap<String, Object>();
        map5.put("customerBean",new CustomerBean("2017-05-16") );
        HashMap<String, Object> map6 = new HashMap<String, Object>();
        map6.put("customerBean",new CustomerBean("2019-01-23") );

        ArrayList<Map<String, Object>> listEnquiry = new ArrayList<Map<String,Object>>();
        listEnquiry.add(map1);
        listEnquiry.add(map2);
        listEnquiry.add(map3);
        listEnquiry.add(map4);
        listEnquiry.add(map5);
        listEnquiry.add(map6);

        ArrayList<CustomerBean> newValues = new ArrayList<>(); //List will contain all objects with 2019 values
        SimpleDateFormat simpleDateFormat = new SimpleDateFormat("yyyy-MM-dd");

        Iterator<Map<String, Object>> itr = listEnquiry.iterator();
        while (itr.hasNext()) {
            Map<String, Object> map = itr.next();
            CustomerBean bean = (CustomerBean) map.get("customerBean");
            //String date = simpleDateFormat.format(bean.getCustomerCreationDate());   // it is giving me date column which contains both year.

            String date = "";
            Calendar cal = Calendar.getInstance();
            cal.setTime(bean.getCustomerCreationDate()); 
            if (cal.get(Calendar.YEAR)==2019) {
                 date = simpleDateFormat.format(bean.getCustomerCreationDate());
                 newValues.add(bean);
                 //System.out.println(date); Simple print the date
            }           
        }
        newValues.forEach((v)->System.out.println(simpleDateFormat.format(v.getCustomerCreationDate())));
    }

    private static class CustomerBean {

        Date date = new Date();

        public CustomerBean(String date) {
            SimpleDateFormat format = new SimpleDateFormat("yyyy-MM-dd");
            try {
                this.date = format.parse(date);
            } catch (ParseException e) {}
        }

        public Date getCustomerCreationDate() {
            return this.date;
        }

    }

}

这给了我输出

2019-03-01
2019-01-23
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