我没有找到我想要的答案，所以我自己找出了答案，并希望与您分享。这些是：Python equivalent of zip for dictionaries既不实现“默认值”（又称最长风味），也不保持顺序。
OrderedDict？具有：
from collections import OrderedDict
o1 = OrderedDict([("key_a", "a1"), ("key_b", "b1")])
o2 = OrderedDict([("key_a", "a2"), ("key_h", "h2")])
o3 = OrderedDict([("key_c", "c3")])
o4 = OrderedDict([("key_x", "x4")])
如何从传递的每个OrderedDict中获取成对的键值和相应的压缩值，但是如果缺少该值，则使用None？
expected_result = [
('key_a', ('a1', 'a2', None, None)),
('key_b', ('b1', None, None, None)),
('key_h', (None, 'h2', None, None)),
('key_c', (None, None, 'c3', None)),
('key_x', (None, None, None, 'x4')),
]
答案 0 :(得分：1)
@blhsing提供了最可爱的solution。这是另一种选择。 在python 2和3中工作：
def zip_ordered_mappings_default(*mappings):
collected_keys = set()
for key in (key for mapping in mappings for key in mapping):
if key not in collected_keys:
collected_keys.add(key)
yield key, tuple(collection.get(key) for collection in mappings)
# usage:
assert list(zip_ordered_mappings_default(o1, o2, o3, o4)) == expected_result
保留结果项的顺序，并等同于根据传递的dict的键创建的有序集的并集。即新密钥显示在末尾。
该解决方案非常通用，也可以与常规dict一起使用：
assert dict(zip_ordered_mappings_default(dict(o1), dict(o2), dict(o3), dict(o4))) == {
'key_a': ('a1', 'a2', None, None),
'key_b': ('b1', None, None, None),
'key_h': (None, 'h2', None, None),
'key_c': (None, None, 'c3', None),
'key_x': (None, None, None, 'x4')
}
当然不会保留dicts项的顺序，但是结果值中的元组会反映函数参数的顺序。
答案 1 :(得分：1)
您可以使用列表推导对从给定字典的所有键创建的<div id="header"></div>
<h2 id="page-title">Create Item</h2>
<div id="create-customer-form" class="row">
<form id="form" action="/create-item" method="POST" class="col s4 offset-m4">
<div class="row">
<div class="input-field col s12">
<select name="collection" id="myDropdown" class="materialSelect">
<option disabled selected>Choose Season</option>
</select>
<label>Collection</label>
</div>
</div>
<div class="row">
<div class="input-field col s12">
<input placeholder="Type" name="type" type="text" class="validate">
<label class="label" for="type">Type</label>
</div>
</div>
<div class="row">
<div class="input-field col s12">
<input placeholder="Model" name="model" type="text" class="validate">
<label class="label" for="model">Model</label>
</div>
</div>
<div class="row">
<div class="input-field col s12">
<input placeholder="Color" name="color" type="text" class="validate">
<label class="label" for="color">Color</label>
</div>
</div>
<div class="row">
<div class="input-field col s12">
<input placeholder="Price" name="price" type="number" class="validate">
<label class="label" for="price">Price</label>
</div>
</div>
<div class="row">
<div class="input-field col s12">
<textarea placeholder="Short Description" name="description" type="text"
class="materialize-textarea validate"></textarea>
<label class="label" for="description">Short Description</label>
</div>
</div>
<div class="row">
<div class="input-field col s12">
<input placeholder="Barcode" name="barcode" type="number" class="validate" data-length="9">
<label class="label" for="barcode">Barcode</label>
</div>
</div>
<div id="submit-btn">
<a id="submit-link" class="waves-effect waves-light btn create-btn"><i
class="material-icons left">add</i>create</a>
</div>
</form>
</div>
<script src="../main.js"></script>
<script src="scripts/jQuery.js" type="text/javascript"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/materialize/1.0.0/js/materialize.min.js"></script>
<script>
$(document).ready(function () {
$.ajax({
url: '/collections',
}).then(function (options) {
$.each(options, function (key, value) {
var $newOpt = $("<option>").attr("value", value.name_year).text(value.name_year);
$("#myDropdown").append($newOpt);
});
$("#myDropdown").trigger('contentChanged');
});
});
$('.materialSelect').formSelect();
$('.materialSelect').on('contentChanged', function () {
$(this).formSelect();
});
document.addEventListener('DOMContentLoaded', function () {
var elems = document.querySelectorAll('select');
var instances = M.FormSelect.init(elems);
});
document.getElementById("submit-link").onclick = function () {
document.getElementById("form").submit();
}
</script>
进行迭代，并输出键值元组，其值是具有生成器表达式的元组，该表达式遍历字典并返回每个字典中给定键的值：
OrderedDict使def zip_dicts(*dicts):
return [(k, tuple(d.get(k) for d in dicts)) for k in OrderedDict.fromkeys(k for d in dicts for k in d)]
返回：
zip_dicts(o1, o2, o3, o4)