Question

在我的网站上，有一个搜索框，用户可以输入内容并搜索该词，无论该词是否在mySQL数据库中。

我的代码：

$search_text = $_POST['srch-text'];

$sql = "SELECT * FROM search WHERE content LIKE '%$search_text%';";

$result = mysqli_query($dbcon, $sql);
$number_of_results = $result->num_rows;

如果任何人输入数据库中存在的两个单词，则工作正常。假设任何人都提供输入“ ABCD XYZ”。在此，数据库中存在ABCD，但数据库中不存在XYZ。然后它不返回任何结果。我想显示ABCD单词的结果。

Answer 1

您可以使用正则表达式。如果使用空格分隔单词，则需要用# simple query to get top 10 messages from order timeline query { order(id: "gid://shopify/Order/618806837270") { events(first: 100) { edges { node { __typename message createdAt id } } } } }替换它们：

[
  {
    "order": {
      "events": {
        "edges": [
          {
            "node": {
              "__typename": "BasicEvent",
              "message": "Order was placed on XXXXXXX.",
              "createdAt": "2018-11-08T22:16:54Z",
              "id": "gid://shopify/BasicEvent/9349083824150"
            }
          },
          {
            "node": {
              "__typename": "BasicEvent",
              "message": "Received new order <a href=\"https://XXXXXXX.myshopify.com/admin/orders/618806837270\">#1183</a>.",
              "createdAt": "2018-11-08T22:16:55Z",
              "id": "gid://shopify/BasicEvent/9349083856918"
            }
          },
          {
            "node": {
              "__typename": "BasicEvent",
              "message": "XXXXXXX fulfilled 1 item from Shopify.",
              "createdAt": "2019-02-04T17:26:00Z",
              "id": "gid://shopify/BasicEvent/14072023547926"
            }
          },
          {
            "node": {
              "__typename": "BasicEvent",
              "message": "This order was archived.",
              "createdAt": "2019-02-04T17:26:00Z",
              "id": "gid://shopify/BasicEvent/14072023580694"
            }
          },
          {
            "node": {
              "__typename": "CommentEvent",
              "message": "this is a comment",
              "createdAt": "2019-02-04T17:26:15Z",
              "id": "gid://shopify/CommentEvent/14072023875606"
            }
          }
        ]
      }
    }
  },
  {
    "cost": {
      "requestedQueryCost": 103,
      "actualQueryCost": 8,
      "throttleStatus": {
        "maximumAvailable": 1000,
        "currentlyAvailable": 992,
        "restoreRate": 50
      }
    }
  }
]

您还应该使用参数传递字符串，而不是用用户输入来修饰查询字符串。因此，本示例使用|作为参数的占位符。

Answer 2

虽然可以使用正则表达式，但我会使用php的explode函数创建一个数组，然后执行多个SQL查询或使用%作为{glue}进行implode。 / p>

Answer 3

您可以将字符串分成两个字符串，并以空格''作为分隔符这是一个SQL脚本，您可以轻松将其转换为mysql

declare @s as varchar(100)
declare @s1 as varchar(100)
declare @s2 as varchar(100)

set @s='STRING1 STRING2'
declare @n as int
set @n=charindex(' ',@s)
if @n>0 
begin
set @s1=substring(@s,1,@n-1)
set @s2=substring(@s,@n+1,len(@s))
end

select @s1 [mystring1],@s2[mystring2]

然后替换查询而不是

$sql = "SELECT * FROM search WHERE content LIKE '%$search_text%';";

作者

$sql = "SELECT * FROM search WHERE content LIKE '%'+@string1+'%' or content LIKE '%'+@string1+'%'

这是等效的mysql脚本

set @s='STRING1 STRING2';

set @n=LOCATE(' ',@s,1);

set @s1=substring(@s,1,@n-1);
set @s2=substring(@s,@n+1,LENGTH(@s));


select @s1 "mystring1",@s2"mystring2";

如果一个单词正确而另一个错误，SQL搜索将无法返回结果

3 个答案: