BigQuery更新失败,但仅在使用Python API批处理时

时间:2019-03-14 15:41:11

标签: google-bigquery

我正在尝试使用批处理更新语句来更新表。 DML查询可在BigQuery Web UI中成功执行,但是在进行批处理时,第一个查询成功,而其他失败。为什么会这样?

查询示例:

query = '''
update `project.dataset.Table`
set my_fk = 1234
where other_fk = 222 and
  received >= PARSE_TIMESTAMP("%Y-%m-%d %H:%M:%S", "2018-01-22 05:28:12") and 
  received <= PARSE_TIMESTAMP("%Y-%m-%d %H:%M:%S", "2018-01-26 02:31:51")
'''

示例代码:

job_config = bigquery.QueryJobConfig()
job_config.priority = bigquery.QueryPriority.BATCH

queries = [] # list of DML Strings
jobs = []
for query in queries:
    job = client.query(query, location='US', job_config=job_config)
    jobs.append(job)

作业输出:

for job in jobs[1:]:
    print(job.state)
    # Done

    print(job.error_result)
    # {'message': 'Cannot set destination table in jobs with DML statements',
    # 'reason': 'invalidQuery'}

    print(job.use_legacy_sql)
    # False

    print(job.job_type)
    # Query

2 个答案:

答案 0 :(得分:1)

您的代码似乎在一次更新中就可以正常工作。这就是我尝试使用客户端API的python 3.6.5和v1.9.0

MapViewOfFile

如果这不能帮助您解决问题,请检查配置并提供完整的代码和错误日志

顺便说一句,我也在命令行中对此进行了验证

from google.cloud import bigquery
client = bigquery.Client()

query = '''
UPDATE `project.dataset.table` SET msg = null WHERE x is null
'''

job_config = bigquery.QueryJobConfig()
job_config.priority = bigquery.QueryPriority.BATCH
job = client.query(query, location='US', job_config=job_config)

print(job.state)
# PENDING

print(job.error_result)
#  None

print(job.use_legacy_sql)
# False

print(job.job_type)
# Query

答案 1 :(得分:1)

我怀疑问题出在插入第一个作业后,job_config由BigQuery API填充了某些字段(尤其是destination)。然后,第二个作业将失败,因为它将是在作业配置中带有目标表的DML语句。您可以使用以下方法进行验证:

for query in queries:
    print(job_config.destination)
    job = client.query(query, location='US', job_config=job_config)
    print(job_config.destination)
    jobs.append(job)

要解决此问题,您可以避免对所有作业重复使用相同的job_config

for query in queries:
    job_config = bigquery.QueryJobConfig()
    job_config.priority = bigquery.QueryPriority.BATCH
    job = client.query(query, location='US', job_config=job_config)
    jobs.append(job)