我有一个UIView
,每次我在另一个视图中按一个按钮时都会显示
@IBOutlet weak var view1: UIView!
@IBOutlet weak var view2: UIView!
@IBAction func showView(_ sender: Any) {
view2.isHidden = false
}
我想要添加一个轻击手势,该手势允许我每次在视图外部单击时都隐藏view2,并且由于这些视图是可拖动的,因此我希望第二个视图在隐藏时不可被点击(因此,如果我在我看来,我不冒险移动它。 这是我尝试过的:
var gesture : UITapGestureRecognizer?
override func viewDidLoad() {
super.viewDidLoad()
NotificationCenter.default.addObserver(self,
selector: #selector(closeView), name: NSNotification.Name("CloseView"), object: nil)
gesture = UITapGestureRecognizer(target: self, action: #selector(ViewController.closeView))
}
@objc func closeView() {
if view2.isHidden == false {
view2.isUserInteractionEnabled = true
view2.isHidden = false
self.view.removeGestureRecognizer(gesture!)
} else {
view2.isHidden = true
view2.isUserInteractionEnabled = true
self.view.addGestureRecognizer(gesture!)
}
}
let closeTapGesture = UITapGestureRecognizer(target: view, action: #selector(getter: view2.isHidden)
view.addGestureRecognizer(closeTapGesture)
没有一项工作,我该怎么办?
答案 0 :(得分:1)
您的轻击手势只能处理closeView。
@objc func closeView() {
view2.isHidden = true
view2.isUserInteractionEnabled = false
gesture?.isEnabled = false
}
然后单击显示您的view2的按钮应调用此按钮。
func showView() {
view2.isHidden = false
view2.isUserInteractionEnabled = true
gesture?.isEnabled = true
}
答案 1 :(得分:1)
您需要检查是否确实在view2之外点击了
var gesture : UITapGestureRecognizer?
override func viewDidLoad() {
super.viewDidLoad()
NotificationCenter.default.addObserver(self,
selector: #selector(closeView), name: NSNotification.Name("CloseView"), object: nil)
let gesture = UITapGestureRecognizer(target: self, action: #selector(closeView(_:)))
view.addGestureRecognizer(gesture)
self.gesture = gesture
}
@objc private func closeView(_ tapGestureRecognizer: UITapGestureRecognizer) {
let location = tapGestureRecognizer.location(in: view2)
guard view2.isHidden == false,
!view2.bounds.contains(location) else { //We need to have tapped outside of view 2
return
}
view2.isHidden = true
}