Question

是否可以将具有NOT IN，IN和UNION运算符的子查询转换为联接？我需要使用无连接子查询的查询，因此spring jpa可以理解

 SELECT * 
  FROM CONTACT 
  WHERE partner_idpartner = (
     SELECT partner_idpartner 
     FROM BUSINESSCHANNEL WHERE idBusinessChannel in (
       select idbusinessFrom from business WHERE idbusiness = 5943
     )
   )  
   and idcontact not in (
     SELECT CONTACT_IDCONTACT FROM businesscontact 
     WHERE BUSINESS_IDBUSINESS=5943
   )   
  UNION
  SELECT *  
  FROM CONTACT 
  WHERE partner_idpartner = (
    SELECT partner_idpartner 
    FROM BUSINESSCHANNEL WHERE idBusinessChannel in (
      select idbusinessTo FROM business WHERE idbusiness = 5943
    )
  )  
   and idcontact not in (
    SELECT CONTACT_IDCONTACT FROM businesscontact 
    WHERE BUSINESS_IDBUSINESS=5943
  )

Answer 1

尝试一下：

SELECT    DISTINCT CONTACT.*
FROM      CONTACT
JOIN      BUSINESSCHANNEL
ON        CONTACT.partner_idpartner = BUSINESSCHANNEL.partner_idpartner
JOIN      business
ON        (BUSINESSCHANNEL.idBusinessChannel = business.idbusinessFrom
AND       business.idbusiness = 5943)
OR        (BUSINESSCHANNEL.idBusinessChannel = business.idbusinessTo)
AND       business.idbusinessroute = 5943)
LEFT JOIN businesscontact
ON        CONTACT.idcontact = businesscontact.CONTACT_IDCONTACT 
AND       BUSINESS_IDBUSINESS = 5943
WHERE     businesscontact.CONTACT_IDCONTACT IS NULL

Answer 2

您可以将所有这些子查询转换为联接。缺点是您失去了可读性，并且可能会产生巨大的中间结果，您必须使用DISTINCT才能摆脱它。这可能是非常昂贵的。 NOT IN可以转换为反联接（外部联接，然后选择不匹配的行），这是另一种模式，可能会产生不希望的大中间结果。

SELECT DISTINCT c.*  
FROM contact c
JOIN businesschannel bc ON bc.partner_idpartner = c.partner_idpartner
JOIN business b ON bc.idbusinesschannel IN (b.idbusinessfrom, b.idbusinessto)
                AND b.idbusiness = 5943 
LEFT JOIN businesscontact bco ON bco.contact_idcontact = c.idcontact
                              AND bco.business_idbusiness = 5943
WHERE bco.contact_idcontact IS NULL;

Answer 3

尝试以下查询：我没有测试

DECLARE @tblNotInIUdContact TABLE (  CONTACT_IDCONTACT INT)
DECLARE @tblIdBusinessFrom TABLE (   IdBusiness INT)
DECLARE @tblIdBusinessTo TABLE (     IdBusiness INT)
DECLARE @tblIdPartner TABLE (    partner_idpartner INT)

INSERT INTO @tblNotInIUdContact(CONTACT_IDCONTACT)
SELECT CONTACT_IDCONTACT FROM businesscontact WHERE BUSINESS_IDBUSINESS=5943

INSERT INTO @tblIdBusinessFrom(IdBusiness)
select idbusinessFrom from business  WHERE idbusiness=5943

INSERT INTO @tblIdBusinessTo(IdBusiness)
select idbusinessTo FROM business    WHERE idbusinessroute=5943

INSERT INTO @tblIdPartner(partner_idpartner)
SELECT partner_idpartner FROM BUSINESSCHANNEL bc
INNER JOIN @tblIdBusinessFrom bf ON bc.partner_idpartner = bf.IdBusiness

INSERT INTO @tblIdPartner(partner_idpartner)
SELECT partner_idpartner FROM BUSINESSCHANNEL bc
INNER JOIN @tblIdBusinessTo bf ON bc.partner_idpartner = bf.IdBusiness



SELECT * FROM CONTACT c
    INNER JOIN @tblIdPartner p ON c.partner_idpartner = p.partner_idpartner  
EXCEPT
SELECT * FROM CONTACT c
    INNER JOIN @tblNotInIUdContact ic ON c.idcontact = ic.CONTACT_IDCONTACT

Answer 4

在这里，你去

替换为：使用内部联接
替换不在以下位置的内容：使用左外部联接tab2，其中tab2.col为null
替换联合，我创建一个临时表#mycontact，其结构与联系

从1 = 0的联系人中选择*进入我的联系人

插入#mycontact 选择 *   来自联系人TA

内部加入   （从BUSINESSCHANNEL T0中选择partner_idpartner   内部联接（从业务WHERE idbusiness = 5943中选择idbusinessFrom）T0.idBusinessChannel = T1.idbusinessFrom上的T1）   左外部联接（来自业务联系人的SELECT CONTACT_IDCONTACT，WHERE BUSINESS_IDBUSINESS = 5943）T2   在T0.idcontact = T2.CONTACT_IDCONTACT上   其中T2.CONTACT_IDCONTACT为null）TA.partner_idpartner = TB.partner_idpartner上的TB

插入#mycontact

选择*
  从联系TC   内部联接（
```
(SELECT partner_idpartner FROM BUSINESSCHANNEL  T0
INNER JOIN (  select idbusinessTo FROM business     WHERE idbusinessroute=5943) T1 on T0.idBusinessChannel=T1.idbusinessFrom)  

left outer join ( SELECT CONTACT_IDCONTACT FROM businesscontact WHERE BUSINESS_IDBUSINESS=5943)  T2
on T0.idcontact=T2.CONTACT_IDCONTACT
```
其中T2.CONTACT_IDCONTACT为空）
```
TD on TC.partner_idpartner=TD.partner_idpartner
```
从#mycontact

如何使用联接将IN，NOT IN，UNION转换为SQL查询

4 个答案: