Question

我有PHP代码：

model_poisson_training<- glm(training_m ~ training_X, family="poisson")
summary(model_poisson_training)
coef.poisson<-model_poisson_training$coefficients

我正在尝试在表中添加一列（如果不存在），并立即用相同的日期（2000-12-02）将所有添加的行填充到此添加的列中。但是我认为这段代码有问题：

$link_multiq = mysqli_connect($host, $user, $password, $dbname);
mysqli_set_charset($link_multiq, "utf8");

$sql = 'SET @preparedStatement = (SELECT IF(
    (SELECT COUNT(*)
    FROM INFORMATION_SCHEMA.COLUMNS
     WHERE table_name = "ring" 
     AND table_schema = "test1_serv" 
     AND column_name = "date_make_count"
     ) > 0, 
     "SELECT 1;", 
     "ALTER TABLE ring ADD date_make_count DATE;UPDATE ring SET date_make_count = '2000-12-02';"
     )); 
     PREPARE alterIfNotExists FROM @preparedStatement; 
     EXECUTE alterIfNotExists; 
     DEALLOCATE PREPARE alterIfNotExists;';

mysqli_multi_query($link_multiq, $sql);     
mysqli_close($link_multiq);

我不知道如何正确编写此部分。我尝试过：

...UPDATE ring SET date_make_count = '2000-12-02';

和其他方式，但是不起作用。请帮忙！

PHP + MySQL，添加列并填写

0 个答案: