我想更改以下元素的样式:
http(s)://<localhost:7071 or azurefunchost>/<routePrefix defined in host.json, default is api>/<function name>?uri=<uri defined in app.route, like / or /hi or /hello, even /hello/peter-pan?name=peter>
完整的svg代码:
<path d="M0 573.96 L0 595.28 L64.96 595.28 L64.96 573.96 L0 573.96 L0 573.96 Z" class="st8"/>
我仅设法更改了文本的笔触,但没有更改背景色。简单地设置fill不会产生任何效果,因此我想删除st8类,但得到消息路径。removeAttribute不是函数。
<g id="shape487-256" v:mID="487" v:groupContext="shape" transform="translate(707.533,-425.236)">
<title>Sheet.487</title>
<desc>Claims Management</desc>
<v:textBlock v:margins="rect(4,4,4,4)" v:tabSpace="42.5197"/>
<v:textRect cx="32.478" cy="584.619" width="64.96" height="21.314"/>
<path d="M0 573.96 L0 595.28 L64.96 595.28 L64.96 573.96 L0 573.96 L0 573.96 Z" class="st8"/>
<text x="21.21" y="582.22" class="st9" v:langID="1033"><v:paragraph v:horizAlign="1"/><v:tabList/>Claims <tspan
x="9.92" dy="1.2em" class="st10">Management</tspan></text> </g>
答案 0 :(得分:0)
要删除一个类,请使用:
paths.classList.remove("st8");
它不会删除属性,但是我猜在这种情况下没关系。
答案 1 :(得分:0)
我设法通过选择正确的子元素来更改背景颜色,高度赞赏的更优雅的解决方案。
function highlightTrend01(){
//Claims Management
var e = document.getElementById("shape487-256");
// e.setAttribute("stroke","blue"); setting stroke works
var children = e.children;
for (var i = 0; i < children.length; i++) {
var c = children[i];
// console.log(c);
// var cId = c.getAttribute("id");
var attrClass = c.getAttribute("class");
if (c.tagName == "path" && attrClass == "st8"){
console.log("Tag name: " + c.tagName + " class: " + attrClass);
// c.removeAttribute("class");
c.style["fill"] = "orange"
}
}
}