Question

我想将年龄范围转换为年龄数值。我使用def Age（x）和If语句进行转换，但是它不起作用并给出错误的结果。我附加了我执行的步骤和结果的图像。我使用的数据集是BlackFriday。请帮助我澄清错误。谢谢！ enter image description here

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Answer 1

鉴于SshClient client = SshClient.setupDefaultClient(); // override any default configuration... client.setSomeConfiguration(...); client.setOtherConfiguration(...); client.start();结果中显示的内容，年龄为try (ClientSession session = client.connect(user, host, port).verify(timeout).getSession()) { session.addPasswordIdentity(password); session.auth.verify(timeout); // User-specific factory try (SftpClient sftp = DefaultSftpClientFactory.INSTANCE.createSftpClient(session)) { // use sftp here } }的简单str.extract和fillna似乎可以做到：

// calculate the start timestamp
$startdatetime = strtotime($startTimeInput);
// calculate the end timestamp
$enddatetime = strtotime($endTimeInput);
// calulate the difference in seconds
$difference = $enddatetime - $startdatetime;
// hours is the whole number of the division between seconds and SECONDS_PER_HOUR
$hoursDiff = $difference / 3600;
// and the minutes is the remainder
$minutesDiffRemainder = $difference % 3600;
// output the result
echo $hoursDiff . "hours " . $minutesDiffRemainder . "mins";

让我们考虑以下示例：

$datetime1 = new DateTime($startTimeInput);
$datetime2 = new DateTime($endTimeInput);
$interval = $datetime1->diff($datetime2);
echo $interval->format('%Y years, %M months, %D days, %I minutes, %S seconds');

Answer 2

一个简单的函数，将age_range修改为：

这是我们的年龄范围

temp_df['age_range'].unique()

array([70, '18-25', '26-35', '36-45', '46-55', '56-70'], dtype=object)

修改年龄的功能

def mod_age(df):
for i in range(df.shape[0]):
    if(df.loc[i,'age_range']==70):
        df.loc[i,'age_range']=70
    elif(df.loc[i,'age_range']=='18-25'):
        df.loc[i,'age_range']=(18+25)//2
    elif(df.loc[i,'age_range']=='26-35'):
        df.loc[i,'age_range']=(26+35)//2
    elif(df.loc[i,'age_range']=='36-45'):
        df.loc[i,'age_range']=(36+45)//2
    elif(df.loc[i,'age_range']=='46-55'):
        df.loc[i,'age_range']=(46+55)//2
    elif(df.loc[i,'age_range']=='56-70'):
        df.loc[i,'age_range']=(56+75)//2

 age_range  family_size marital_status  sum
2   70         2        Single          4
25  40         4        Single          2
5   21         2        Married         4
32  50         3        Single          3
13  30         2        Single          5

年龄范围至年龄数值（python）

2 个答案: