当用户输入名字时,如果它是空白,具有数字或字母数字或具有非ASCII字符,我将不会将其插入数据库。
在下面的代码中,该代码不接受有效的输入,仅当我使用len
和isDigit
这两个条件时,它才有效。
while (len(f_name) == 0 or f_name.isdigit()
或
f_name.encode('ascii',errors='ignore') or f_name.isalnum()):
Create new user: Y/N ?y
Enter first name: ui
First name cannot be empty or have numeric values
有人可以解释如何解决此问题吗?谢谢你的时间。其余代码如下:
import sqlite3
#connect a built in function to connect or create db
conn=sqlite3.connect('phonebook.db')
#Create a cursor function which allows us to do sql operations
crsr=conn.cursor()
#This function to check if table exists
def create_Table():
#Check if the table exists or not
crsr.execute("SELECT name FROM sqlite_master WHERE name='phonebook'")
tableSize=len(crsr.fetchall())#will be greater than 0 if table exists
if tableSize>0:
print()
else:
#create the table
crsr.execute(""" Create Table phonebook(
FirstName text NOT NULL,
LastName text,
Phone text PRIMARY KEY NOT NULL)
""")
#check if table got created or not
crsr.execute("SELECT name FROM sqlite_master WHERE name='phonebook'")
tableSize = len(crsr.fetchall()) # will be greater than 0 if table exists
if tableSize > 0:
print('Table was created successfully')
#This function will create new users and insert in DB
def create_User():
try:
while True:
rsp = input('Create new user: Y/N ?')
if rsp == 'y':
f_name = input('Enter first name: ')
# First name cannot be empty or have numeric values
while (len(f_name) == 0 or f_name.isdigit() or f_name.encode('ascii',errors='ignore') or f_name.isalnum()):
print('First name cannot be empty or have numeric values')
f_name = input('Enter first name: ')
l_name = input('Enter last name: ')
phone = input('Enter phone number: ')
crsr.execute("INSERT INTO phonebook VALUES (:FirstName, :LastName, :Phone)",
{'FirstName': f_name, 'LastName': l_name, 'Phone': phone})
conn.commit()
if rsp == 'n':
break
except:
print('UNIQUE constraint failed: phone number already exists')
答案 0 :(得分:2)
使用isalpha
确保字符串仅是字母:
f_name = input('Enter first name: ')
if f_name and f_name.isalpha():
# your ACCEPTED logic here
还有,如果需要检查那些字母是否是ASCII,则可以将它们的编码长度与其自身进行比较:
f_name = input('Enter first name: ')
if f_name and f_name.isalpha() and len(f_name) == len(f_name.encode()):
# your ACCEPTED logic here
EDIT (添加空字符串检查)(即if f_name
)
答案 1 :(得分:1)
如果您对正则表达式感到满意,则可以通过以下方式测试条件“必须不为空”和“必须不包含数字”:
import re
# match one or more characters that range from a to z or A to Z
username_check = re.compile(r'[a-zA-Z]+')
...
while True:
if rsp == 'y':
f_name = input('Enter first name: ')
while not username_check.fullmatch(f_name):
print('First name cannot be empty or have numeric values')
f_name = input('Enter first name: ')
关于正则表达式的好处是,您可以灵活地扩展当前的最小解决方案,以测试非常具体的模式:
import re
# allow unicode word characters
allowed = re.compile(r'\w+')
# numbers are still not allowed
forbidden = re.compile(r'\d')
while True:
f_name = input('Enter first name: ')
while not (allowed.fullmatch(f_name) and not forbidden.search(f_name)):
print('First name cannot be empty or have numeric values')
f_name = input('Enter first name: ')