我有一个文件,它是电影的字幕(sub.srt或文本文件)。但是我想知道是否有一种删除文件的所有行号和时间线的简便方法。例如
85
00:07:39,250 --> 00:07:41,469
We got to be smart.
We're a ways from being finished.
86
00:07:41,628 --> 00:07:43,380
I can do this all week.
87
00:07:43,546 --> 00:07:44,547
We're gonna.
88
00:07:44,714 --> 00:07:49,352
We're like the Comanches,
little brother, raiding wherever we please
必须证明为
We got to be smart.
We're a ways from being finished.
I can do this all week.
We're gonna.
We're like the Comanches,
little brother, raiding wherever we please
或连续体形状:
We got to be smart. We're a ways from being finished. I can do this all week. We're gonna. We're like the Comanches, little brother, raiding wherever we please
python或其他任何编程语言都能达到我们这个目标吗?
答案 0 :(得分:2)
您可以检查line
是否以digit
开头,并且只有在没有的情况下才打印:
list.txt:
85
00:07:39,250 --> 00:07:41,469
We got to be smart.
We're a ways from being finished.
86
00:07:41,628 --> 00:07:43,380
I can do this all week.
87
00:07:43,546 --> 00:07:44,547
We're gonna.
88
00:07:44,714 --> 00:07:49,352
We're like the Comanches,
little brother, raiding wherever we please
因此:
with open("list.txt", 'r') as fp:
content = fp.readlines()
# you may also want to remove empty lines
content = [l.strip() for l in content if l.strip()]
for line in content:
if not line[0].isdigit():
print(line)
输出:
We got to be smart.
We're a ways from being finished.
I can do this all week.
We're gonna.
We're like the Comanches,
little brother, raiding wherever we please
编辑:
使用print(line, end = " ")
在一行中获取输出:
输出:
We got to be smart. We're a ways from being finished. I can do this all week. We're gonna. We're like the Comanches, little brother, raiding wherever we please