我的任务是从PDF中提取特定坐标的文本。
我已经使用Apache Pdfbox客户端进行数据提取。
要使用PDF以毫米为单位的PDF更改工具从PDF获取x,y,高度和宽度坐标。当我在矩形中传递值时,这些值不会变为空值。
public String getTextUsingPositionsUsingPdf(String pdfLocation, int pageNumber, double x, double y, double width,
double height) throws IOException {
String extractedText = "";
// PDDocument Creates an empty PDF document. You need to add at least
// one page for the document to be valid.
// Using load method we can load a PDF document
PDDocument document = null;
PDPage page = null;
try {
if (pdfLocation.endsWith(".pdf")) {
document = PDDocument.load(new File(pdfLocation));
int getDocumentPageCount = document.getNumberOfPages();
System.out.println(getDocumentPageCount);
// Get specific page. THe parameter is pageindex which starts with // 0. If we need to
// access the first page then // the pageIdex is 0 PDPage
if (getDocumentPageCount > 0) {
page = document.getPage(pageNumber + 1);
} else if (getDocumentPageCount == 0) {
page = document.getPage(0);
}
// To create a rectangle by passing the x axis, y axis, width and height
Rectangle2D rect = new Rectangle2D.Double(x, y, width, height);
String regionName = "region1";
// Strip the text from PDF using PDFTextStripper Area with the
// help of Rectangle and named need to given for the rectangle
PDFTextStripperByArea stripper = new PDFTextStripperByArea();
stripper.setSortByPosition(true);
stripper.addRegion(regionName, rect);
stripper.extractRegions(page);
System.out.println("Region is " + stripper.getTextForRegion("region1"));
extractedText = stripper.getTextForRegion("region1");
} else {
System.out.println("No data return");
}
} catch (IOException e) {
System.out.println("The file not found" + "");
} finally {
document.close();
}
// Return the extracted text and this can be used for assertion
return extractedText;
}
请建议我的方法是否正确。
答案 0 :(得分:1)
我已使用此PDF tutorialspoint.com/uipath/uipath_tutorial.pdf。在尝试查找文本“比赛的一部分”的地方,该文本的x = 55.6毫米y = 168.8宽度= 210.0毫米,高度= 297.0。但是我得到的是空值
我用这些输入测试了您的方法:
bytes=4
((max=2**(bytes*8)-1))
for ((i=0; i<max; i++)); do
printf -v hex %08x "$i"
cansend slcan0 "7e0#02090${hex}0000000000"
done
(ExtractText测试System.out.println("Extracting like Venkatachalam Neelakantan from uipath_tutorial.pdf\n");
float MM_TO_UNITS = 1/(10*2.54f)*72;
String text = getTextUsingPositionsUsingPdf("src/test/resources/mkl/testarea/pdfbox2/extract/uipath_tutorial.pdf",
0, 55.6 * MM_TO_UNITS, 168.8 * MM_TO_UNITS, 210.0 * MM_TO_UNITS, 297.0 * MM_TO_UNITS);
System.out.printf("\n---\nResult:\n%s\n", text);
)
得到结果
testUiPathTutorial
假设您实际上是在寻找“内容的一部分”,而不是“比赛的一部分”,只是缺少了“ a”;可能是在测量时寻找了可见字母图形的开始,但是实际字形的起源要早于此。如果您选择一个较小的 x ,例如54.6毫米,您还会得到'a'。
考虑到矩形的宽度和高度,获得的不仅仅是“一部分内容”,这也就不足为奇了。
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i
常量,请看一下this answer。