Question

因此，我定义了一个函数，使其返回两个Time对象的总和作为新的Time对象，但是结果Time对象中的分钟总和不能超过59而且我不知道如何实现。

这是我的代码：

from timer import Time

sum_of_time = Time(0, 0)
sum_of_time.hours= time1.hours + time2.hours
sum_of_time.minutes = time1.minutes + time2.minutes

return sum_of_time

if sum_of_time.minutes >= 60: # where I try to make minutes within 0 to 59
    sum_of_time.minutes = sum_of_time.minutes - 60
    sum_of_time.hours = sum_of_time.hours + 1
    return sum_of_time

Answer 1

这就是datetime.timedelta的用途。

from datetime import timedelta

delta1 = timedelta(hours=1, minutes=30)
delta2 = timedelta(minutes=31)
sum_time = delta1 + delta2
print(sum_time) #2:01:00

Answer 2

您想除以60的商和余数；商被加到小时，其余的用作分钟数。

sum_of_time = Time(0,0)
hours = time1.hours + time2.hours
minutes = time1.minutes + time2.minutes
q, r = divmod(minutes, 60)  # e.g. divmod(117, 60) == (1, 57)
hours += q
minutes = r
sum_of_time.hours = hours
sum_of_time.minutes = minutes

这可能应该由Time类的方法来实现。例如：

class Time:
    def __init__(self, h, m):
        self.hours = 0
        self.minutes = 0

    # For simplicity here, assume other is an instance of Time
    def __add__(self, other):
        hours = self.hours + other.hours
        minutes = self.minutes + other.minutes
        q, r = divmod(minutes, 60)
        return Time(hours + q, r)

sum_of_time = time1 + time2

Answer 3

class Time:
    def __init__(self,h,m):
        self.h = h
        self.m = m
        q, r = divmod(m, 60)
        self.h += q
        self.m = r

    def __add__(self, o): 
        return Time(self.h+o.h,self.m+o.m)

    def __str__(self):
        return "{0}:{1}".format(self.h,self.m)



t1 = Time(1,60)
t2 = Time(1,60)
print (t1+t2)

如何在0到59之间的Time类中设置分钟属性

3 个答案: