我有2个简单的模型。首先，一个叫做Builds（mysql），第二个叫做SlotOptions（mongodb）。每个版本可以分配5个插槽。基于https://stackoverflow.com/a/55132863/2513428
select * from `builds` where `builds`.`id` = 37 limit 1
SlotOptions.find({"heroName":{"$in":[37]}},{"typeMap":{"root":"array","document":"array"}})
表。 build_slot_option （mysql）
+----------------+--------+----------------------------------------+
| Name | Type | Desc |
+----------------+--------+----------------------------------------+
| slot_option_id | char50 | // FK, Name of slot option f.e "Hero1" |
| build_id | int | // FK, Build id |
| pos | int | // Number 1-5 |
+----------------+--------+----------------------------------------+
slot_option_id-是包含英雄名称的字符串，实际上不是ID。
示例：
+----------------+----------+-----+
| slot_option_id | build_id | pos |
+----------------+----------+-----+
| Hero1 | 37 | 1 |
| Hero2 | 37 | 2 |
| Hero3 | 37 | 3 |
| Hero4 | 37 | 4 |
| Hero5 | 37 | 5 |
+----------------+----------+-----+
表。 构建（mysql）
+------+------+------------------------+
| Name | Type | Desc |
+------+------+------------------------+
| id | int | // PK, of Builds Table |
| ... | ... | // and other columns |
+------+------+------------------------+
这是构建类和用法示例。
class BuildDB extends Model
{
use HybridRelations;
protected $connection = 'mysql';
public function slots()
{
return $this->belongsToMany(
SlotOptions::class, 'build_slot_option', 'build_id', 'slot_option_id'
);
}
}
BuildDB::with('slots')->find(5);
对于第二个查询，它应该不插入构建ID ，仅在{"$in":[37]}中插入来自tb build_slot_option slot_option_id的所有插槽名称列。例如{"$in":['Hero1','Hero2']}