我知道以前已经有人问过这个问题，但是我正在寻找一种更干净的解决方案。我想按西装和顺序对一手牌进行排序。
以下是我的Deck课程的相关部分：
import card
import random
class Deck:
def __init__(self):
suits = ["Hearts", "Diamonds", "Clubs", "Spades"]
values = ["2", "3", "4", "5", "6", "7", "8", "9", "10", "J", "Q", "K" ,"A"]
self._cards = [card.Card(suit, value) for suit in suits for value in values]
def deal_hand(self):
hand = random.sample(self._cards, 5)
for card in hand:
self._cards.remove(card)
hand.sort(key=lambda x: (x.suit, x.value))
return hand
这是我的卡类：
class Card:
def __init__(self, suit, value):
self.suit = suit
self.value = value
def __repr__(self):
return f"{self.value} of {self.suit}"
但是，当我看玩家的手时，它们仅按衣服排序，而不按值排序。
这是我得到的输出：
John's hand: [10 of Clubs, 2 of Clubs, A of Hearts, 9 of Spades, J of Spades]
Arnold's hand: [K of Clubs, 8 of Diamonds, 7 of Hearts, 9 of Hearts, 7 of Spades]
Alex's hand: [Q of Clubs, 2 of Hearts, 5 of Hearts, 8 of Spades, K of Spades]
Morgan's hand: [5 of Clubs, A of Diamonds, 10 of Hearts, Q of Hearts, 2 of Spades]
其中10个俱乐部排在2个俱乐部之前。另外，x的K将在x的Q之前。
为什么我的lambda只按西装排序？我至少希望其中的10个俱乐部能排在2个俱乐部之后。
有干净的溶液吗？