Question

我正在努力寻找如何在仅1列中放置where条件的情况。

总而言之，我想在数据库中有一列所有票证，并在另一列中包含给定日期的所有票证。

我的SQl请求：

SELECT
  i.created AS creation, l.label AS activite, 
  COUNT(l.label) AS nbTicket, COUNT(l.label) AS nbEntree
FROM label AS l INNER JOIN
     jiraissue AS i
     ON (l.issue = i.id) AND i.issuetype <> 3
GROUP BY activite

所以在这里，我有数据库中的所有票证，但是如果我有带日期的where条件：

SELECT l.label AS activite, SUM(i.timespent/3600/8) AS consomme, SUM(i.timeestimate/3600/8) AS raf, COUNT(l.label) AS nbTicket, 
    SUM(i.timeoriginalestimate/3600/8) AS chargeProvisoire, COUNT(l.label) AS nbEntree 
    FROM label AS l INNER JOIN jiraissue AS i ON (l.issue = i.id)  
    WHERE l.label IN ('Devis','TGC1','TGC2','TGC3','TGC4','TGC5','TGC5-Bis','TGC6','TGC7','TGC8','TGC8-Bis','TGC9','TGC10','TGC10-Bis','TGC12','TGC13','TGC13-Bis','TGC14','TGC50','TGC60')
    AND i.issuetype <> 3 AND i.created LIKE "2014-01-%" GROUP BY activite

我只有2019年1月的机票。

将所有票证包含在==> nbTicket列中并将所有具有'where'子句的票证包含在==> nbEntree中是一种解决方案吗？

Answer 1

您可以在第一个查询中使用条件SUM()，如下所示：

SELECT
  max(i.created) AS creation,
  l.label AS activite, 
  COUNT(*) AS nbTicket,
  SUM(case when i.created LIKE "2019-01-%" then 1 end) AS nbEntree
FROM label AS l INNER JOIN
     jiraissue AS i
     ON (l.issue = i.id) AND i.issuetype <> 3
GROUP BY activite

仅1列的SQL条件

1 个答案: