我具有以下课程结构
public class A {
@Id
public String id;
public List<B> bs;
}
public class B{
public String name;
public List<B> preconditions;
}
如果我返回此类的实例,则会得到嵌套的JSON
结构
{
"id": "3",
"bs": [
{
"name": "abc"
},
{
"name": "drilling",
"preconditions": [
{
"name": "abc"
}
]
}
]
}
我希望先决条件成为引用列表,例如
{
"id": "3",
"bs": [
{
"name": "abc"
},
{
"name": "drilling",
"preconditions":
["abc"]
}
]
}
我该怎么做?前提条件应引用bs
列表中的对象,我将Jersey Web Serevices
和Jackson
用于JSON
生成。
编辑:基于MichałZiober答案: 它工作正常,但是如果我更改bs的顺序,结果将如下所示:
{
"id": "3",
"bs": [
{
"name": "drilling",
"preconditions":
[
{
"name": "abc"
}
]
},"abc"
]
}
我希望对象总是在bs列表中定义,而不是在前提条件列表中
{
"id": "3",
"bs": [
{
"name": "drilling",
"preconditions":
["abc"]
},
{
"name": "abc"
}
]
}
答案 0 :(得分:0)
您需要使用JsonIdentityInfo
批注。您的POJO
类可能如下所示:
class A {
private String id;
@JsonIdentityInfo(property = "name", generator = ObjectIdGenerators.PropertyGenerator.class)
private List<B> bs;
// getters, setters
}
class B {
private String name;
@JsonIdentityInfo(property = "name", generator = ObjectIdGenerators.PropertyGenerator.class)
private List<B> preconditions;
// getters, setters
}
简单的例子:
import com.fasterxml.jackson.annotation.JsonIdentityInfo;
import com.fasterxml.jackson.annotation.JsonInclude;
import com.fasterxml.jackson.annotation.ObjectIdGenerators;
import com.fasterxml.jackson.databind.ObjectMapper;
import com.fasterxml.jackson.databind.SerializationFeature;
import java.util.Arrays;
import java.util.List;
public class JsonApp {
public static void main(String[] args) throws Exception {
ObjectMapper mapper = new ObjectMapper();
mapper.enable(SerializationFeature.INDENT_OUTPUT);
mapper.setSerializationInclusion(JsonInclude.Include.NON_NULL);
B b = new B();
b.setName("abc");
B b1 = new B();
b1.setName("drilling");
b1.setPreconditions(Arrays.asList(b));
A a = new A();
a.setId("3");
a.setBs(Arrays.asList(b, b1));
System.out.println(mapper.writeValueAsString(a));
}
}
打印:
{
"id" : "3",
"bs" : [ {
"name" : "abc"
}, {
"name" : "drilling",
"preconditions" : [ "abc" ]
} ]
}