Question

我需要异步使用db.all()获取所有数据。我不想在回叫中运行其他功能/代码。我想“导出”结果。可以吗？

*我是SQLite的新手*

const sqlite3 = require('sqlite3').verbose()
const db = new sqlite3.Database('./db/subscribers.db')

const createSQLStatement = `CREATE TABLE IF NOT EXISTS subscriptions (id INTEGER PRIMARY KEY AUTOINCREMENT, subscriber TEXT)`
db.run(createSQLStatement)

exports.getAllSubscribers = async () => {
  const $sql = `SELECT * FROM subscriptions`
  return await db.all($sql, (err, rows) => {
    if (err) {
      return
    }

    // I wish to export "rows" which is an array
    return rows
  })
}

在另一个文件中

const { getAllSubscribers } = require('./foo')

getAllSubscribers().then(subs => {

  // subs is not what I expect it to be.
  // I'm getting:
  // Database { open: true, filename: './db/subscribers.db', mode: 65542 }
  // But I do need subs here to loop over and not inside of getAllSubscribers()

})
.catch(e => console.log(e))

我也看过this doc，但似乎没有任何结果能给我带来期望的结果。

Answer 1

使用then和catch时不使用await。

因此，您需要改进第一个脚本：

const sqlite3 = require('sqlite3').verbose()
const db = new sqlite3.Database('./db/subscribers.db')

const createSQLStatement = `CREATE TABLE IF NOT EXISTS subscriptions (id INTEGER PRIMARY KEY AUTOINCREMENT, subscriber TEXT)`
db.run(createSQLStatement)

exports.getAllSubscribers = () => {
  const $sql = `SELECT * FROM subscriptions`
  return db.all($sql, []);
}

在另一个文件中，您可以像这样使用await：

const { getAllSubscribers } = require('./foo')
const getSubscribers = async () => {
    const subscribers = await getAllSubscribers();
};

您可以在此处找到更多示例：https://www.scriptol.com/sql/sqlite-async-await.php

使用节点sqlite3

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