子查询返回的值超过1。无法解析

时间:2019-03-13 11:12:17

标签: sql sql-server

我第二次问这个问题,但找不到答案,请帮忙。 我想用此查询更新我的'MakinelerVeParcalar'表;

UPDATE MakinelerVeParcalar SET Durum = 'Montaj' WHERE ID = 161

我得到了这个错误;

  

消息512,级别16,状态1,过程trgSureUpdate,行31 [批处理开始第0行]子查询返回的值超过1。当子查询遵循=,!=,<,<=,>,> =或将子查询用作表达式时,不允许这样做。

我的trgSureUpdate(Trigger)

ALTER TRIGGER [dbo].[trgSureUpdate]
            ON [dbo].[MakinelerVeParcalar]
            AFTER UPDATE
            AS 
            BEGIN

                DECLARE @count INT
                DECLARE @idinserted INT
                DECLARE @duruminserted VARCHAR(50)
                DECLARE @max INT
                DECLARE @iddeleted INT
                DECLARE @durumdeleted VARCHAR(50)
                DECLARE @datediff INT
                DECLARE @durumbilgisi varchar(50)
                DECLARE @sureinserted INT
                DECLARE @suredeleted INT
                DECLARE @diffdate INT

                SELECT @idinserted = ID from inserted  <-- Line 31
                SELECT @duruminserted = Durum from inserted
                SELECT @iddeleted = ID from deleted
                SELECT @durumdeleted = Durum from deleted

                SET @count = (SELECT count(*) FROM Sure WHERE ID = @idinserted and Asama = @duruminserted)
                SET @max = (SELECT max(SiraNo) FROM Sure WHERE ID = @idinserted)
                SET @durumbilgisi = (SELECT DurumBilgisi FROM DurumBilgisi WHERE ID = @idinserted)
                SET @sureinserted = (SELECT Sure FROM Sure WHERE ID = @idinserted and Asama = @duruminserted)
                SET @suredeleted = (SELECT Sure FROM Sure WHERE ID = @iddeleted and Asama = @durumdeleted)

                IF @duruminserted != @durumdeleted
                BEGIN


                    IF @durumbilgisi != 'Bitti'
                    BEGIN
                        UPDATE Sure Set Cikis = GETDATE() WHERE Asama = @durumdeleted and ID = @idinserted and SiraNo = @max
                        SET @diffdate = DATEDIFF (SECOND,(SELECT Giris FROM Sure WHERE ID = @idinserted and SiraNo = @max),(SELECT Cikis FROM Sure WHERE ID = @idinserted and SiraNo = @max))
                        UPDATE Sure SET Sure = (@diffdate) WHERE ID = @idinserted and SiraNo = @max
                    END
                    INSERT INTO Sure (ID,Asama,Giris,Cikis,Sure,SiraNo) VALUES(@idinserted,@duruminserted,GETDATE(),NULL,0,(@max+1))
                    UPDATE DurumBilgisi SET DurumBilgisi = 'Devam Ediyor' WHERE ID = @idinserted
                END
            END

如果您需要表格,我可以发送所有表格。谢谢...

2 个答案:

答案 0 :(得分:3)

您需要使用subquery子句来限制top中的行:

 SELECT TOP (1) @durumbilgisi = DurumBilgisi 
 FROM DurumBilgisi 
 WHERE ID = @idinserted
 ORDER BY ??

 SELECT TOP (1) @sureinserted = Sure 
 FROM Sure 
 WHERE ID = @idinserted and Asama = @duruminserted
 ORDER BY ??

 SELECT TOP (1) @suredeleted = Sure 
 FROM Sure 
 WHERE ID = @iddeleted and Asama = @durumdeleted
 ORDER BY ??

??排序列,用于指定您的列排序。

答案 1 :(得分:1)

您有两种选择。

首先:-如果返回相同的记录值,则写下来。

 SET @durumbilgisi = (SELECT DISTINCT DurumBilgisi FROM DurumBilgisi WHERE ID = @idinserted)
 SET @sureinserted = (SELECT DISTINCT  Sure FROM Sure WHERE ID = @idinserted and Asama = @duruminserted)
 SET @suredeleted = (SELECT DISTINCT  Sure FROM Sure WHERE ID = @iddeleted and Asama = @durumdeleted)

第二次选择第一条记录

 SET @durumbilgisi = (SELECT TOP 1 DurumBilgisi FROM DurumBilgisi WHERE ID = @idinserted)
 SET @sureinserted = (SELECT TOP 1 Sure FROM Sure WHERE ID = @idinserted and Asama = @duruminserted)
 SET @suredeleted = (SELECT TOP 1 Sure FROM Sure WHERE ID = @iddeleted and Asama = @durumdeleted)