德尔福XE& OmniXML:使用SelectNode()?

时间:2011-04-01 13:17:56

标签: xml delphi delphi-xe omnixml

我将以下XML代码段作为我使用最新OmniXML快照处理的更大XML文件的一部分:

<OrderRequestHeader>
<!-- snipped XML bits here -->
<ShipTo>                                                        
    <Address addressID="">                                      
        <Name xml:lang="en">SOME COMPANY</Name>        
        <PostalAddress name="default">                          
            <DeliverTo>John Doe</DeliverTo>                  
            <Street>123 Any St</Street>                  
            <City>Nowhere</City>                              
            <State>AK</State>                                   
            <PostalCode>99999</PostalCode>                      
            <Country isoCountryCode="US">United States</Country>
        </PostalAddress>                                        
        <Email/>                                                
        <Phone>                                                 
            <TelephoneNumber>                                   
                <CountryCode isoCountryCode=""/>                
                <AreaOrCityCode/>                               
                <Number></Number>                               
            </TelephoneNumber>                                  
        </Phone>                                                
    </Address>                                                  
</ShipTo>
<!-- more XML stuff follows -->
</OrderRequestHeader>

我目前有一个指向<ShipTo>节点的变量,并且想要选择<Name>节点的内容。我正在使用以下代码,但Node2即将出现Nil ...

procedure ProcessXML;
var
    Node1, Node2: IXMLNode;

begin
    Node1 := FindNode(OrderHeader, 'ShipTo');
    // the above is working.  Node points to the <ShipTo> node
    Node2 := SelectNode(Node1, 'Name');
    // the above line doesn't work.  Node2 is Nil
end;

为什么Node2 Nil?根据{{​​1}}中的帮助,OmniXMLUtils.pas将选择一个节点可能超过以下一个级别。肯定有一个SelectNode节点。即使尝试通过<Name>找到节点也会返回一个空列表。我是否以某种方式使用OmniXML?如果没有先选择XPathSelect(Node1, 'Name');节点,是否可以到达<Name>节点?

2 个答案:

答案 0 :(得分:1)

SelectNode可以正常工作,如果你在前面添加双斜杠字符:

var
  FXMLDocument: IXMLDocument;

// Somewhere along the line
  FXMLDocument := CreateXMLDocument
  XMLLoadFromFile(FXMLDocument, 'WhateverFile.xml');
  // or XMLLoadFromAnsiString(FXMLDocument, SomeStringVar);


var
  QryNode, Node: IXMLNode;
begin
  QryNode := FXMLDocument.DocumentElement;
  Node := SelectNode(QryNode, 'ShipTo');
  if Assigned(Node) then
  begin
    QryNode := SelectNode(Node, '//Name');
    if Assigned(QryNode) then
      ShowMessage('ShipTo Name is ' + QryNode.FirstChild.Text)
    else
      ShowMessage('Name not found');
  end;
end;

如果您愿意,XPath也能正常运行:

implementation

var
  FXMLDocument: IXMLDocument;

// Somewhere along the line
  FXMLDocument := CreateXMLDocument
  XMLLoadFromFile(FXMLDocument, 'WhateverFile.xml');
  // or XMLLoadFromAnsiString(FXMLDocument, SomeStringVar);

function GetShipTo: string;
var
  QryNode: IXMLNode;
  Node: IXMLNode;
  NodeList: IXMLNodeList;
begin
  Result := '';
  QryNode := FXMLDocument.DocumentElement;  

  // The following also work:
  // '//Address/Name'
  // '//Name'
  NodeList := XPathSelect(QryNode, '//ShipTo/Address/Name');
  if NodeList.Length > 0 then
    QryNode := NodeList.Item[0]
  else
    QryNode := nil;
  if Assigned(QryNode) then
    Result := QryNode.FirstChild.Text; // Now has 'SOME COMPANY'
end;

答案 1 :(得分:0)

我弄清楚我做错了什么:我必须指定整个相对路径,而不仅仅是我想要的孙子节点的名称。

从我上面的ProcessXML示例中,我必须像这样填写Node2

Node2 := SelectNode(Node, 'Address/Name');

使用XPath,我必须通过XPathSelect(Node, 'Address/Name');

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