Question

我有一个conversations和conversation_timelines之类的表

对话表格示例

|  id   |   last_active   |   category_id   |
|-------------------------------------------|
|  1    |   1552462134    |        1        |
|  2    |   1552461332    |        1        |
|  3    |   1552462312    |        2        |
|  4    |   1552461772    |        1        |

conversation_timelines 表格示例

|  id   |  conversation_id  |  message  |  created_time  |
|--------------------------------------------------------|
|  1    |        1          |  hi       |  1552462066    |
|  2    |        1          |  hello    |  1552462172    |
|  3    |        1          |  world    |  1552462188    |
|  4    |        2          |  another  |  1552462141    |

我要查询的是计数 conversation_timelines 中有 created_time > conversation's last_active 次会话中的记录数。category_id= 1

结果世界就像

|  conversation_id  |  count  |
|         1         |    2    |
|         2         |    1    |

Answer 1

像下面一样使用join和group by

  SELECT ct.conversation_id,count(ct.message)
  FROM conversation_timelines ct
  INNER JOIN  conversation c on c.id=ct.conversation_id and c.category_id=1
  and ct.created_time>c.last_active
  GROUP BY ct.conversation_id

Answer 2

您可以使用以下解决方案，将JOIN与GROUP BY结合使用：

SELECT c.id AS `conversation_id`, COUNT(ct.id) AS `count`
FROM conversation c INNER JOIN conversation_timelines ct ON c.id = ct.conversation_id 
WHERE ct.created_time > c.last_active AND c.category_id = 1
GROUP BY c.id

demo on dbfiddle.uk

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2 个答案: