Question

我正在尝试将redux项目导出为node_module，该项目的index.js如下所示（简化）：

import { createStore, applyMiddleware } from 'redux';
import thunk from 'redux-thunk';
import promiseMiddleware from 'redux-promise-middleware';
import App from './App.jsx';

const middlewares = [thunk.withExtraArgument(), promiseMiddleware()];
const middlewareEnhancer = applyMiddleware(...middlewares);
const preloadedState = {};

const store = createStore(
    rootReducer,
    preloadedState,
    middlewareEnhancer
);

 const ExampleModule = (props) => {
    return (
        <Provider store={store}>
            <App />
        </Provider>
    );
};

export default ExampleModule;

在我的主应用程序中：

...
import ExampleModule from 'example-module';

class Application extends React.Component {
    render() {
        return <ExampleModule />;
    }
}

function mapStateToProps({ state }) {
    return {
        state: state
    };
}

function mapDispatchToProps(dispatch) {
    return { 
        actions: bindActionCreators(require('..').actions, dispatch) 
    };
}

export default connect(mapStateToProps, mapDispatchToProps)(Application);

这将引发错误： bundle.js:349 Uncaught Invariant Violation: Could not find "store" in either the context or props of "Connect(App)". Either wrap the root component in a <Provider>, or explicitly pass "store" as a prop to "Connect(App)"

我假设是因为这实际上会创建嵌套的<Providers>，这与Redux的一家商店的方法背道而驰。

我的问题是发布具有Redux存储的node_module的最佳方法是什么？

如何将react-redux项目导出为node_module

0 个答案: