我有测试:
class ContacsBLOTest extends TestCase
{
public function testsearch()
{
$Ctrl= new ContactsBLO;
$data=['id'=>1,'name'=>'The Manh','phone'=>'123456566','address'=>'180 cao lo','note'=>''];
$data=[(object)$data];
$mock_data=\Mockery::mock('DB');
$mock_data->shouldReceive('all')->andReturn($data);
$mock_ctrl= new ContactsBLO;
$mock_ctrl->select=$mock_data;
$result=$mock_ctrl->search('manh');
$this->assertNotNull($result);
}
这是ContacsBLO类:
class ContactsBLO
{
public $db,$not_allow,$Validation;
public function __construct(){
$this->db=new DB;
$this->not_allow=['"','\'','%'];
$this->Validation = new ContactValidation;
}
public function search($request=null){
$length=strlen($request);
for ($i=0;$i<$length;$i++) {
$forbidden=$this->not_allow;
if(in_array($request[$i],$forbidden)){
return (['messenger'=>'We are not allow special character in your request','old_input'=>$request]);
}
else{
return $data=$this->db->select('*',$request);
}
}
}
}
DB :: class(我定义连接到数据库并定义选择方法:
class DB
{
public $obj = null;
public $table = 'contacts';
public function __construct(){
$dsn="mysql:host=".HOST."; dbname=".DB_NAME;
$this->obj = new \PDO($dsn, DB_USER, DB_PASS);
$this->obj->query("set names 'utf8' ");
}
public function select($row=null,$query=null) {
$sql='SELECT '.$row.' FROM '.$this->table.' '.$query;
$data = $this->obj->prepare($sql);
$data->execute();
return $data->fetchAll(\PDO::FETCH_CLASS);
}
}
但是当我运行xdebug并运行此测试时,$ forbidden为null,这意味着模拟方法返回真实数据,而不是模拟数据。我不知道为什么。 任何人都可以帮助我!拜托!
答案 0 :(得分:1)
您从来没有将模拟插入到您的类中,除了使用new
关键字创建类实例时,还很难模拟。在这种情况下,您唯一的机会就是使用类别名。
为了避免所有这些,您可以通过ContactsBLO构造函数传入数据库实例。
class ContacsBLOTest extends TestCase
{
public function testSearch()
{
$data = ['id'=>1,'name'=>'The Manh','phone'=>'123456566','address'=>'180 cao lo','note'=>''];
$data = json_decode(json_encode($data));
$mock_contact = \Mockery::mock(DB::class);
$mock_contact->shouldReceive('select')->andReturn($data);
$Ctrl = new ContactsBLO($mockDB);
$result = $Ctrl->search('manh');
$this->assertNotNull($result);
}
}
class ContactsBLO
{
public $db;
public $not_allow;
public $Validation;
public function __construct(DB $db) {
$this->db = $db;
$this->not_allow = ['"','\'','%'];
$this->Validation = new ContactValidation;
}
public function search($request=null){
$length=strlen($request);
for ($i=0;$i<$length;$i++) {
$forbidden = $this->not_allow;
if(in_array($request[$i],$forbidden)){
return (['messenger'=>'We are not allow special character in your request','old_input'=>$request]);
}
else{
return $data = $this->db->select('*',$request);
}
}
}
}
我使用此代码对其进行了测试,并且效果很好。请检查数据库类是否已导入到测试文件的顶部。您还必须将Test
附加到所有测试文件名和类(请参见上文)。
答案 1 :(得分:0)
我将其更改为:
$mock_data=\Mockery::mock('DB');
$mock_data->shouldReceive('select')->andReturn($data);
$mock_ctrl= new ContactsBLO;
$mock_ctrl->db=$mock_data;
$result=$mock_ctrl->search();
它正在为我工作,谢谢大家的帮助