Question

背景：我正在遍历数据库数据并将其输出到表中的页面。我的循环首先输出标头信息，但标头就是我所说的未准备好前端的信息。

例如：child_0_birthday需要更改为Child 1 Birthday。

到目前为止，我的财产是：

    //Define table header section here
        foreach ($fields as $k => $v){
        $html .= '<th class="manage-column" data-key="'.esc_html($v).'">'.updateHeaderName(vsz_cf7_admin_get_field_name($v)) .'</th>';
                                    }

    //This function would do the clean up

    $devHeaderNames = array("child_0_birthday", "child_0_fname", "child_0_lname", "child_0_age");

function updateHeaderName($oldHeader) {

    if (in_array($oldHeader, $devHeaderNames))
      {
     //This is where I would want to change the value of $oldHeader to something cleaner and spit it back out. I could write a very long if statement but there has to be a better way. 
        if ($oldHeader == child_0_fname){
            $newHeader = "Child 1 First Name";
            return $newHeader;
        }else if...
      }
   }

问题：是否有一种更有效的方法，然后编写一个很长的if语句来更改显示在每列标题中的字符串？

Answer 1

您可以只使用数组来转换键和值的关联。假设$header = "child_0_birthday"：

$devHeaderNames = array("child_0_birthday" => "Child 1 Birthday"); //etc...

if(isset($devHeaderNames[$header])) {
    $header = $devHeaderNames[$header];
}

遍历数组时更新标头字符串

1 个答案: