我编写了一个Java程序,该程序包含三个相关的类;员工,客户和合同。在我的主要方法中,我已经创建了一个包含所有3个类的各种实例的数组;
// Create Clients
Client Client1 = new Client(1, "Client 1", 0);
Client Client2 = new Client(2, "Client 2", 0);
// Create Array of Clients
Client[] clients = new Client[] {Client1, Client2};
// Create Contracts
Contract Contract1 = new Contract("Contract 1", 1, 850, 4, 0, 1, 0);
Contract Contract2 = new Contract("Contract 2", 2, 500, 4, 0, 1, 0);
Contract Contract3 = new Contract("Contract 3", 3, 1500, 3, 0, 1, 0);
// Create Array of Contracts
Contract[] contracts = new Contract[] {Contract1, Contract2, Contract3};
// Create Employees
Employee Employee1 = new Employee(1, "Bradley", 0);
Employee Employee2 = new Employee(2, "Patrick", 0);
Employee Employee3 = new Employee(3, "Erin", 0);
Employee Employee4 = new Employee(4, "Jim", 0);
Employee Employee5 = new Employee(5, "Fredrick", 0);
// Create Array of Employees
Employee[] employees = new Employee[] {Employee1, Employee2, Employee3, Employee4, Employee5};
我在Contract.Java中有一个函数,名为AssignContractToEmployeeWithLeastContracts,它带有2个参数,一组雇员和合同。功能是:
// Assign contract to employee with least contracts
public void assignContractToEmployeeWithLeastContracts(Employee[] employees, Contract contract) {
// Assign to employee with minimum contracts
int minContract = Integer.MAX_VALUE;
Employee employeeWithMinContracts = null;
for (Employee employee : employees) {
if (employee.getCurrentlyAssignedContracts() < minContract) {
// swap min and employee if true
employeeWithMinContracts = employee;
minContract = employeeWithMinContracts.getCurrentlyAssignedContracts();
}
}
employeeWithMinContracts.assignContract(employeeWithMinContracts, contract);
}
我的问题是,如果2名员工都分配了相同(最少)张合同,那么我该如何处理。如果发生这种情况,我该如何随机选择一名员工?我曾尝试在foreach循环中实现种子,但不断破坏一切。
任何帮助都将得到帮助,
谢谢, B
答案 0 :(得分:3)
如果您希望两名以上的员工共享相同数量的最低合同,那么您需要从中随机挑选。您可以通过列出最低限度合同并随机选择一个合同来完成此操作。
ORA-00936: missing expression
答案 1 :(得分:2)
如果我的理解正确,那么您想使用assignContractToEmployeeWithLeastContracts
方法将合同随机分配给其中一名雇员,如果他们拥有相同数量的合同。
因为当前您将其分配给合同数量最少的第一位员工。
您的方法将变为:
public void assignContractToEmployeeWithLeastContracts(Employee[] employees, Contract contract) {
int minContract = Integer.MAX_VALUE;
List<Employee> employeesWithMinContracts = new ArrayList<Employee>();
for (Employee employee : employees) {
if (employee.getCurrentlyAssignedContracts() < minContract) {
employeesWithMinContracts.clear();
employeesWithMinContracts.add(employee);
minContract = employee.getCurrentlyAssignedContracts();
} else if (employee.getCurrentlyAssignedContracts() == minContract) {
employeesWithMinContracts.add(employee);
}
}
int randomIndex = (int)(Math.random() * employeesWithMinContracts.size());
employeesWithMinContracts.get(randomIndex).assignContract(contract);
}
我们将利用Math.random
返回一个介于[0,1]之间的值的事实,从而可以随机找到我们的employeeWithMinContracts列表索引。
备注:
注意,我删除了Employee
方法中的assignContract
作为参数。由于此方法已在相关的Employee
上调用。
此外,您的实例名称应以小写字母开头,以符合Java标准:
Contract1
成为contract1
Employee1
成为employee1
等等...