我无法编译 Binding.scala 的简单示例,而且作为新手,我不知道如何解决它。也许自述文件有些过时了? https://github.com/ThoughtWorksInc/Binding.scala-sample处的示例甚至更旧,并且会导致弃用警告。
我的代码(基本上是我从README中扎在一起的),甚至简化了一些:
import com.thoughtworks.binding.dom
import org.scalajs.dom.document
import scala.scalajs.js.annotation.JSExport
@JSExport
object SampleMain {
@dom
def table = {
<table border="1" cellPadding="5">
<thead>
<tr>
<th>Name</th>
<th>E-mail</th>
</tr>
</thead>
<tbody>
</tbody>
</table>
}
@JSExport
def main(): Unit = {
dom.render(document.body, table)
}
}
fastOptJS
导致编译错误:
SampleMain.scala:25:9: overloaded method value render with alternatives:
[error] (parent: org.scalajs.dom.raw.Node,children: com.thoughtworks.binding.Binding[com.thoughtworks.binding.Binding.BindingSeq[org.scalajs.dom.raw.Node]],dummy: Unit)Unit <and>
[error] (parent: org.scalajs.dom.raw.Node,children: com.thoughtworks.binding.Binding.BindingSeq[org.scalajs.dom.raw.Node])Unit <and>
[error] (parent: org.scalajs.dom.raw.Node,child: com.thoughtworks.binding.Binding[org.scalajs.dom.raw.Node])Unit
[error] cannot be applied to (org.scalajs.dom.raw.HTMLElement, scala.xml.Elem)
[error] dom.render(document.body, table)
[error] ^
我怀疑类型推断存在问题,并尝试了以下类型注释:def table: com.thoughtworks.binding.Binding[org.scalajs.dom.html.Table]
,但这引起了另一个错误:
SampleMain.scala:11:6: type mismatch;
[error] found : scala.xml.Elem
[error] required: com.thoughtworks.binding.Binding[org.scalajs.dom.html.Table]
[error] (which expands to) com.thoughtworks.binding.Binding[org.scalajs.dom.raw.HTMLTableElement]
[error] <table border="1" cellPadding="5">
[error] ^
我希望能得到一个解释,这里出了什么问题。
答案 0 :(得分:3)
原来的问题是在我的情况下paradise
编译器插件没有被使用。我仅在子项目中使用Binding.scala构建SBT多项目,并且addCompilerPlugin
不会传播到子项目。为了使其正常工作,需要将其添加到子项目的设置中,如下所示:
lazy val client = (project in file("client"))
.settings(
libraryDependencies ++= Seq(
"com.thoughtworks.binding" %%% "dom" % "11.6.0"
),
addCompilerPlugin("org.scalamacros" % "paradise" % "2.1.0" cross CrossVersion.full)
)
.enablePlugins(ScalaJSPlugin)
在addCompilerPlugin
的顶层拥有build.sbt
之前,它不起作用并导致了编译错误。