我正在编写一个递归函数来解决一个问题,在这个问题上,您实际上是在尝试查找所有组合以达到给定数量的目标总和,并且每个数字都小于特定限制。
我编写的代码如下:
results = []
def findSchedulesHelper(workHours_left, dayHoursLimit, days_left, res):
if workHours_left < 0:
return
elif workHours_left > 0 and days_left == 0:
return
elif workHours_left == 0 and days_left != 0:
for i in range(days_left):
res.append(0)
results.append(res)
return
elif days_left == 0 and workHours_left == 0:
results.append(res)
return
else:
for i in range(dayHoursLimit + 1):
res.append(i)
findSchedulesHelper(workHours_left - i, dayHoursLimit, days_left - 1, res)
res.pop()
def findSchedules(workHours, dayHours, pattern):
# Write your code here
num_question_mark = 0
total_hours_so_far = 0
for char in pattern:
if char == "?":
num_question_mark += 1
else:
total_hours_so_far += int(char)
hours_left_to_fill = workHours - total_hours_so_far
for i in range(dayHours + 1):
findSchedulesHelper(hours_left_to_fill - i, dayHours, num_question_mark - 1, [i])
print results
findSchedules(3,2,"??2??00")
但这给出了错误的答案。
如果我更改一行并且做到这一点:
results = []
def findSchedulesHelper(workHours_left, dayHoursLimit, days_left, res):
if workHours_left < 0:
return
elif workHours_left > 0 and days_left == 0:
return
elif workHours_left == 0 and days_left != 0:
for i in range(days_left):
res.append(0)
results.append(res)
return
elif days_left == 0 and workHours_left == 0:
results.append(res)
return
else:
for i in range(dayHoursLimit + 1):
findSchedulesHelper(workHours_left - i, dayHoursLimit, days_left - 1, res + [i])
def findSchedules(workHours, dayHours, pattern):
# Write your code here
num_question_mark = 0
total_hours_so_far = 0
for char in pattern:
if char == "?":
num_question_mark += 1
else:
total_hours_so_far += int(char)
hours_left_to_fill = workHours - total_hours_so_far
for i in range(dayHours + 1):
findSchedulesHelper(hours_left_to_fill - i, dayHours, num_question_mark - 1, [i])
print results
findSchedules(3,2,"??2??00")
然后一切都正确。我真的很困惑为什么会这样。我尝试进行一些调试,发现append和pop未能按我预期的方式工作。如果任何人都可以解释我执行此功能的两种方式之间的确切区别,那将是很好的。