Question

我正在尝试编写一个仅返回句子前八个单词的函数。但是，如果第一句话少于八个单词，我只想返回第一句话-而不是前八个单词。

例如，如果测试的句子是“这是一个比八个单词长得多的句子，但是仅输出前八个单词。”

输出为：“这是一个更长的句子”

如果我添加了标点符号（该函数正在查找）以将输入更改为“这是一个句子。该词比八个单词长得多，但是仅输出前八个单词。”

输出为：“这是一个句子。”

代码如下：

#> 
#> $`weight/individual %.% kg[2]`

Answer 1

在处理句子定界符之前，您似乎将字符串拆分成单词数组，这似乎使您感到困惑。只需先处理句子定界符，然后就可以使用slice将单词数限制为最多8个。

仅使用split，slice和join的紧凑版本：

const longer = 'This is a sentence that is much longer than eight words, but only the first eight words will be outputted.';
const shorter = 'This is a sentence. that is much longer than eight words, but only the first eight words will be outputted.';

const trunc = (s) => {
  return s.split(/[.?!]/)[0].split(' ').slice(0, 8).join(' ');
}

console.log(trunc(longer));
// This is a sentence that is much longer

console.log(trunc(shorter));
// This is a sentence

如果您需要保留8个单词或更少的句子的结尾标点符号，则可以在组合中添加search：

const longer = 'This is a sentence that is much longer than eight words, but only the first eight words will be outputted.';
const shorter = 'This is a sentence. that is much longer than eight words, but only the first eight words will be outputted.';

const trunc = (s) => {
  let i = s.search(/[.?!]/) + 1;
  return s.slice(0, i ? i : s.length).split(' ').slice(0, 8).join(' ');
}

console.log(trunc(longer));
// This is a sentence that is much longer

console.log(trunc(shorter));
// This is a sentence.

Answer 2

const checkString = str => str.substr(0, /[.?!]/.exec(str).index + 1).split(' ').filter((_, idx) => idx < 8).join(' ');

console.log(checkString("This is a sentence that is much longer than eight words, but only the first eight words will be outputted."));

console.log(checkString("This is a sentence. This is another sentence."));

console.log(checkString("This is a sentence? This is another sentence."));

console.log(checkString("This is a sentence! This is another sentence."));

从字符串的第一句话中获取最多8个单词

2 个答案: