Question

我有两个对象

Client = [id, name]
Order = [id, clientId]

我有一个订单数组，并想在一个垫子表中显示它们。我已启动并运行所有内容（因此显示ID和ClientID），但是如何将“订单”中的ClientID与我的客户结合起来才能显示真实姓名？

我什么都找不到。可能没有在Google上搜索正确的内容，也无法针对该简单任务提出一个建议！

最好的问候！

Answer 1

您可以仅按clientId将订单分组，然后将每个客户端的结果订单数组添加到客户端对象：

const clients = [
  { id: 1, name: "first" },
  { id: 2, name: "second" }
];

const orders = [
  { id: 1, clientId: 1, text: "First Order" },
  { id: 2, clientId: 2, text: "Second Order" },
  { id: 3, clientId: 1, text: "Third Order" }
];

const groupedOrders = {};
orders.forEach(order => {
  if (!groupedOrders[order.clientId]) {
    groupedOrders[order.clientId] = [];
  }
  groupedOrders[order.clientId].push(order);
});

const groupedClientsAndOrders = clients.map(client => {
  return Object.assign({}, client, { orders: groupedOrders[client.id] || [] });
});

这将产生一个新的数组，如下所示：

[
    {
        "id": 1,
        "name": "first",
        "orders": [
            {
                "id": 1,
                "clientId": 1,
                "text": "First Order"
            },
            {
                "id": 3,
                "clientId": 1,
                "text": "Third Order"
            }
        ]
    },
    {
        "id": 2,
        "name": "second",
        "orders": [
            {
                "id": 2,
                "clientId": 2,
                "text": "Second Order"
            }
        ]
    }
]

如果您需要每个订单的客户，还可以执行以下操作：

const clients = [
  { id: 1, name: "first" },
  { id: 2, name: "second" }
];

const orders = [
  { id: 1, clientId: 1, text: "First Order" },
  { id: 2, clientId: 2, text: "Second Order" },
  { id: 3, clientId: 1, text: "Third Order" }
];

const joinedOrders = orders.map(order => {
  const client = clients.filter(c => c.id == order.id)[0];
  return Object.assign({}, order, { client: client });
});

为MatTableDataSource连接两个数组-Angular / TS

1 个答案: