Question

在我的.gitlab-ci.yml中，我正在尝试使用findstr命令。

findstr /c:"%SOLUTION_DIR%" gitlab.dif > founded.ref

如果该命令在gitlab.dif中与“％SOLUTION_DIR％”不匹配，则将％ERRORLEVEL％设置为1。

GitLab跑步者似乎将其解释为工作失败。

ERROR: Job failed: exit status 1

有什么解决方法吗？

编辑：

我的.gitlab-ci.yml文件

stages:
  - check
  - build

check_diff:
  stage: check
  script:
    - git diff --name-only origin/develop...HEAD > _gitlab_diff.txt
    - git diff --name-only HEAD~1 >> _gitlab_diff.txt
  artifacts:
    paths:
    - _gitlab_diff.txt
  only:
    refs:
    - merge_requests
    - develop

.generic_build_job:
  stage: build
  dependencies: 
    - check_diff
  before_script:
    - findstr /c:"%SOLUTION_DIR%" "_gitlab_diff.txt" > _check_%SOLUTION_FILE%.txt
    - for /f %%i in ("_check_%SOLUTION_FILE%.txt") do set size=%%~zi
    - if %size% == 0 exit 0
    - cd %SOLUTION_DIR%
  script:
    - '"%NUGET%" restore "%SOLUTION_FILE%"'
    - '"%MSBUILD%" /consoleloggerparameters:ErrorsOnly /maxcpucount /nologo /property:Configuration=Release /verbosity:quiet "%SOLUTION_FILE%"'
  only:
    refs:
    - merge_requests
    - develop

MyApp1:
  variables:
    SOLUTION_DIR: "MyApp1/"
    SOLUTION_FILE: "MyApp1.sln"
  extends: .generic_build_job
  only:
    changes:
      - MyApp1/*

MyApp2:
  variables:
    SOLUTION_DIR: "MyApp2/"
    SOLUTION_FILE: "MyApp2.sln"
  extends: .generic_build_job
  only:
    changes:
      - MyApp2/*

Answer 1

我发现了使用批处理脚本的解决方法。

这是我的skip.bat：

findstr /c:%1 %2 >nul 2>&1
if not %errorlevel% == 0 exit 0

Answer 2

您可以：

findstr / c：％1％2> nul 2>＆1 |退出（0）

由于此命令，您的工作将再也不会失败

Windows上的GitLab运行程序并处理＆％ERRORLEVEL％

2 个答案: