我想知道如何使用基于类的视图制作类别页面视图,我知道如何通过使用get_object_or_404(category, slug=None)
在基于函数的视图中制作类别页面视图,但是我对如何在基于类的视图中做到这一点感到困惑。我试图用谷歌搜索,但是在类视图中找不到与此相关的任何内容。
我知道我可以使用基于函数的视图,但是我在整个项目中都使用了基于类的视图,所以我也想在这里使用它们。
我的代码
models.py
from django.db import models
from django.utils import timezone
from slugger import AutoSlugField
from django.contrib.auth.models import User
from django.urls import reverse
# Create your models here.
def upload_location(instance, filename):
return "%s/%s" %(instance.slug, filename)
class Category(models.Model):
title = models.CharField(max_length= 60)
slug = AutoSlugField(populate_from='title')
parent = models.ForeignKey('self',blank=True, null=True ,related_name='children',on_delete=models.CASCADE)
updated = models.DateTimeField(auto_now=True, auto_now_add=False)
timestamp = models.DateTimeField(auto_now=False, auto_now_add=True)
class Meta:
verbose_name_plural = 'categories'
def __unicode__(self):
return self.title
def __str__(self):
return self.title
def get_absolute_url(self, slug=None):
return reverse("posts-detail", kwargs={"slug": self.slug})
class Post(models.Model):
title = models.CharField(max_length=120)
slug = AutoSlugField(populate_from='title')
image = models.ImageField(
upload_to=upload_location,
null=True,
blank=True,
)
category = models.ForeignKey(Category, on_delete=models.CASCADE, related_name='postcategory')
content = models.TextField()
date_posted = models.DateTimeField(default=timezone.now)
author = models.ForeignKey(User, on_delete=models.CASCADE)
class Meta:
ordering = ['-date_posted']
def __str__(self):
return self.title
def get_absolute_url(self, slug=None):
return reverse("posts-detail", kwargs={"slug": self.slug})
urls.py
from django.urls import path
from django.urls import path, include
from .views import PostView, PostDetailView,LatestPostView, CategoryPostListView
urlpatterns = [
path('', PostView.as_view(), name='posts-home'),
path('latest/', LatestPostView.as_view(), name='posts-latest'),
path('<slug>', PostDetailView.as_view(), name='posts-detail'),
path('category/<slug>', CategoryPostListView.as_view(), name='category-detail'),
]
views.py
from django.contrib.auth.mixins import LoginRequiredMixin, UserPassesTestMixin
from django.shortcuts import redirect, render,get_object_or_404
#class based view
from django.views.generic import ListView, DetailView
from .models import Post, Category
class PostView(ListView):
template_name = 'posts/home.html'
model = Category
context_object_name = 'all_categs'
def get_queryset(self):
if self.request.user.is_authenticated:
return Category.objects.all()
else:
return Category.objects.all().exclude(title__iexact = 'Featured')[:6]
def get_context_data(self):
if not self.request.user.is_authenticated:
fcategory = Category.objects.get(title__iexact = 'Featured')
context = super(PostView, self).get_context_data()
context['latest_posts'] = Post.objects.exclude(category= fcategory).order_by('-date_posted')[0:6]
context['featured_posts'] = Post.objects.all().filter(category= fcategory).order_by('-date_posted')[0:6]
return context
else:
fcategory = Category.objects.get(title__iexact = 'Featured')
context = super(PostView, self).get_context_data()
context['latest_posts'] = Post.objects.order_by('-date_posted')
context['featured_posts'] = Post.objects.all().filter(category= fcategory).order_by('-date_posted')[0:6]
return context
# def get_success_url(self):
# return reverse('home') #add your path
class LatestPostView(LoginRequiredMixin, ListView):
template_name = 'posts/post_latest.html'
model = Post
context_object_name = 'Posts'
ordering = ['-date_posted']
paginate_by = 6
class PostDetailView(LoginRequiredMixin,DetailView):
model = Post
template_name = 'posts/post_detail.html'
class CategoryPostListView(LoginRequiredMixin, ListView):
model = Category
template_name = 'posts/category_detail.html'
# def get_queryset(self):
# category = get_object_or_404(Category, )
我想到了在get_queryset
内定义CategoryPostListView
。但是我不确定它是否会起作用。
答案 0 :(得分:1)
首先,如果您正在使用ListView并要显示帖子列表,则需要model = Post
。
接下来,您可以在get_queryset方法中调用get_object_or_404
。您可以使用`self.kwargs ['slug']从URL访问slug
。
最后,您可以过滤查询集以仅返回该类别中的帖子。
class CategoryPostListView(LoginRequiredMixin, ListView):
model = Post
template_name = 'posts/category_detail.html'
def get_queryset(self):
category = get_object_or_404(Category, slug=self.kwargs['slug'])
return super(CategoryPostListView, self).get_queryset().filter(category=category)
请注意,您的问题与文档中的dynamic filtering section非常相似。
答案 1 :(得分:0)
是的。您可以在基于类的视图中使用get_object_or_404
。只需将其添加到您的CategoryPostListView
:
class CategoryPostListView(LoginRequiredMixin, ListView):
model = Post
template_name = 'posts/category_detail.html'
def get_queryset(self):
category = get_object_or_404(Category, slug=self.kwargs['slug'])
# do another stuffs here
return Post.objects.filter(category=category)
有关更多信息,您可以在django官方网站上阅读dynamic filtering in class-based views