let number = 0;
function increase() {
for (var i = 0; i < 1; i++) {
document.getElementById("number").innerHTML = number += 1;
}
}
if (number = 50) {function double() {
for (var i = 0; i < 2; i++) {
document.getElementById("number").innerHTML = number += 1;
}
}
}
.button1border {
border: black 3px solid;
margin: 10px 1280px 0px 0px;
width: 60px;
}
<!DOCTYPE="html">
<html>
<link rel="stylesheet" type="text/css" href="/style.css">
<button type="button" onclick="increase()">
by 1
</button>
<button onclick="double()">
by 2
</button>
<div class="button1border">
number:
<div id="number">
</div>
</div>
<script src="script.js" type="text/javascript"></script>
</html>
单击第二个按钮时,数字立即变为50,而不是该按钮不起作用。有人可以尝试解决此问题,以便当数字达到50(50次单击)时,第二个按钮起作用?如果数字低于50,则第二个按钮不起作用。
答案 0 :(得分:2)
缩进是您的朋友,您的函数也是回调,它们仅在绑定到元素的事件上触发时执行
let number = 0;
function increase() {
document.getElementById("number").innerHTML = number += 1;
}
function double() {
if (number >= 50) {
for (var i = 0; i < 2; i++) {
increase();
}
}
}
.button1border {
border: black 3px solid;
margin: 10px 1280px 0px 0px;
width: 60px;
}
<!DOCTYPE="html">
<html>
<link rel="stylesheet" type="text/css" href="/style.css">
<button type="button" onclick="increase()">
by 1
</button>
<button onclick="double()">
by 2
</button>
<div class="button1border">
number:
<div id="number">
</div>
</div>
<script src="script.js" type="text/javascript"></script>
</html>
答案 1 :(得分:0)
您可以定位第二个按钮,并且按钮元素具有
属性disabled
。
因此,当您增加数字时,请检查您的数字是否> = 50并禁用它disable = false
let number = 0;
function increase() {
for (var i = 0; i < 1; i++) {
document.getElementById("number").innerHTML = number += 1;
}
}
if (number = 50) {function double() {
for (var i = 0; i < 2; i++) {
document.getElementById("number").innerHTML = number += 1;
}
}
}
<!DOCTYPE="html">
<html>
<link rel="stylesheet" type="text/css" href="/style.css">
<button type="button" onclick="increase()">
by 1
</button>
<button onclick="double()">
by 2
</button>
<div class="button1border">
number:
<div id="number">
</div>
</div>
<script src="script.js" type="text/javascript"></script>
</html>
var number = 0;
let btnTwo = document.getElementById("btnTwo");
function increase() {
for (var i = 0; i < 1; i++) {
document.getElementById("number").innerHTML = number += 1;
}
if(number >= 50){
btnTwo.disabled = false;
}
}
if (number == 50) {function double() {
for (var i = 0; i < 2; i++) {
document.getElementById("number").innerHTML = number += 1;
}
}
}
.button1border {
border: black 3px solid;
margin: 10px 1280px 0px 0px;
width: 60px;
}
<!DOCTYPE="html">
<html>
<link rel="stylesheet" type="text/css" href="/style.css">
<button type="button" onclick="increase()">
by 1
</button>
<button id="btnTwo" onclick="double()" disabled>
by 2
</button>
<div class="button1border">
number:
<div id="number">
</div>
</div>
<script src="script.js" type="text/javascript"></script>
</html>
类似tihs。
答案 2 :(得分:0)
您真的不需要在这里进行for循环。
let number = 0;
function increase() {
if (number <= 50) {
document.getElementById("number").innerHTML = number += 1;
}
}
function double() {
if (number > 50) {
document.getElementById("number").innerHTML = number += 2;
}
}
.button1border {
border: black 3px solid;
margin: 10px 1280px 0px 0px;
width: 60px;
}
<!DOCTYPE="html">
<html>
<link rel="stylesheet" type="text/css" href="/style.css">
<button type="button" onclick="increase()">
by 1
</button>
<button onclick="double()">
by 2
</button>
<div class="button1border">
number:
<div id="number">
</div>
</div>
<script src="script.js" type="text/javascript"></script>
</html>