Question

我正在使用C ++ libcurl将数据发布到Web服务，并且一切正常。我想使用Web服务响应（Json）作为参数在另一个Web服务中进行另一个POST。你们能帮我吗？非常感谢

//FIRST POST
curl_easy_setopt(curl, CURLOPT_URL, url1.c_str());
curl_easy_setopt(curl, CURLOPT_POSTFIELDS, postData.c_str());
curl_easy_setopt(curl, CURLOPT_IPRESOLVE, CURL_IPRESOLVE_V4);
curl_easy_setopt(curl, CURLOPT_TIMEOUT, 10);
curl_easy_setopt(curl, CURLOPT_FOLLOWLOCATION, 1L);
std::unique_ptr<std::string> httpResponse1(new std::string());
curl_easy_setopt(curl, CURLOPT_WRITEFUNCTION, callback);
curl_easy_setopt(curl, CURLOPT_WRITEDATA, httpResponse1.get());
curl_easy_perform(curl);

//SECOND POST
curl_easy_setopt(curl, CURLOPT_URL, url2.c_str());
curl_easy_setopt(curl, CURLOPT_POSTFIELDS, httpResponse1);
curl_easy_setopt(curl, CURLOPT_IPRESOLVE, CURL_IPRESOLVE_V4);
curl_easy_setopt(curl, CURLOPT_TIMEOUT, 10);
curl_easy_setopt(curl, CURLOPT_FOLLOWLOCATION, 1L);
std::unique_ptr<std::string> httpResponse2(new std::string());
curl_easy_setopt(curl, CURLOPT_WRITEFUNCTION, callback);
curl_easy_setopt(curl, CURLOPT_WRITEDATA, httpResponse2.get());
curl_easy_perform(curl);

Answer 1

我建议您根据需要的公共libcurl示例阅读并进行此类工作：

在内存中接收：getinmemory.c
从内存中发帖（并在内存中也收到该响应）：postinmemory.c

c ++ libcurl-使用先前卷曲的响应作为对另一个卷曲的参数

1 个答案: