Question

我正在创建一个可以回答上述问题的代码，而我做了以下

scores=[23,11,19,13,26]
names1=["joe","tom","bob","fred","barry"]
average=(scores[0]+scores[1]+scores[2]+scores[3]+scores[4])/5
print("the average is",average,"and the following are above average:")
if scores[0] > average:
    print(names[0],scores[0])
if scores[1] > average:
    print(names[1],scores[1])
if scores[2] > average:
    print(names[2],scores[2])
if scores[3] > average:
    print(names[3],scores[3])
if scores[4] > average:
    print(names[4],scores[4])

但是由于未知原因，它显示IndexError：列表索引超出范围

我不确定如何解决此错误？

Answer 1

您应该循环在名称和分数对上，为高于平均水平的每个分数打印一行。请注意，内置函数sum在内部循环得分。

scores = [...]
names1 = [...]
average = sum(scores)/5
print("The average is {} and the following are above average".format(average))
for name, score in zip(names1, scores):
    if score > average:
        print(name, score)

Answer 2

有一件事，就是您有一个错字，您的列表被称为names1，而不是名字，因此我将其更改。如果这样做，您的代码将起作用，但是可以通过使用for循环来使其更好。

这应该有效：

scores=[23,11,19,13,26]
names=["joe","tom","bob","fred","barry"]
average=(scores[0]+scores[1]+scores[2]+scores[3]+scores[4])/5
print("the average is",average,"and the following are above average:")
for i in range(len(scores)):
    if scores[i] > average:
        print(names[i],scores[i])

给出5个名字和分数的列表，打印出高于平均水平的名字

2 个答案: