Question

我目前正在尝试弄清楚如何搜索数组以查找数组中的特定元素。用户将输入他们要查找的名称，我的程序应将用户所坐的座位返回给用户。添加乘客的方法是另一种方法。因此，如果我在座位5上坐着一个叫“蒂姆·琼斯”的人，如果我使用这种方法，我将键入“蒂姆·琼斯”，并且程序应该告诉我蒂姆·琼斯在座位5上。

我得到的当前输出只是else语句，无论我如何尝试都找不到乘客。有小费吗？预先感谢。

private static void findPassengerSeat(String airplaneRef[]) {
    String passengerName;
    Scanner input = new Scanner(System.in);
    System.out.println("Enter passenger's name."); // asks user for passenger name.
    passengerName = input.next(); // user input stored under variable passengerName.
    for (int i = 0; i < airplaneRef.length; i++) { // for i, if i is less than the length of the array airplaneRef, increment i.
        if (airplaneRef[i].equalsIgnoreCase(passengerName)) { // iterates through all elements in the array, ignoring case sensitivity and looks for the passenger.
            int seat = i;
            System.out.println(passengerName + " is sitting in seat s" + seat); // prints name of passenger and what seat they are sitting in.
        } else {
            System.out.println("Passenger not found.");
            break;
        }
    }
}

Answer 1

您应该摆脱else，否则，您只需要评估数组的第一个索引并传递其余所有索引即可。

以下内容应具有其魅力：您基本上会浏览所有乘客的列表，并且只有当所有乘客均不符合输入内容时，才声明找不到该乘客。

for (int i = 0; i < airplaneRef.length; i++) { // for i, if i is less than the length of the array airplaneRef, increment i.
    if (airplaneRef[i].equalsIgnoreCase(passengerName)) { // iterates through all elements in the array, ignoring case sensitivity and looks for the passenger.
        int seat = i;
        System.out.println(passengerName + " is sitting in seat s" + seat); // prints name of passenger and what seat they are sitting in.
        return;
    }
}
System.out.println("Passenger not found.");

Java-在数组中查找元素

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